Question

In a sample of 800 U.S. adults, 218 dine out at a restaurant more than once a week. If two U.S adults are selected at random from the population of all U.S. adults without replacement. Assuming the sample is representative of all U.S. adults. (a) Find the probability that both adults dine out more than once per week\

Answer 1

Answer: 0.074

Step-by-step explanation:

Given : The total number of U.S. adults in the sample = 800

The number of U.S. adults dine out at a restaurant more than once a week = 216

The probability for an adult dine out more than once per week :-

$\dfrac{218}{800}$

If another person is selected without replacement ,then

Total adults left = 799

Total adults left who dine out at a restaurant more than once a week = 217

The probability for the second person dine out more than once per week :-

$\dfrac{217}{799}$  

Now, the probability that both adults dine out more than once per week :-

$\dfrac{218}{800}\times\dfrac{217}{799}=0.074$