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3 years ago

It costs $15 per hour to rent a bike. The additional fee for a helmet is $3 for the entire ride.

Mathematics

1 answer:

STatiana [176]3 years ago

3 0

Answer:

okay and how many hours?

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Please help 20 points

irinina [24]

The answer would be 10

7 0

2 years ago

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Determine the equation of each line with the following properties:

iris [78.8K]

Answer:

a) y =2/3 x + 7.

b) x = -1

c) y = -4/5 x - 1/5

d) y = -3/2 x + 5/2.

Step-by-step explanation:

a) Intercept form y = mx + b where m = 2/3 and b = 7

b) y can take any value but x is always -1.

c) Slope m = (-1-3)/ (1 - -4)

= -4/5

Using point-slope form where m = -4/5 and x1 y1 = 1 , -1:

y - y1 = m(x - x1)

y - -1 = -4/5(x - 1)

y + 1 = -4/5x + 4/5

y = -4/5 x - 1/5

d) The slope m of the line perpendicular to this line is:

-1 / 2/3

m = -3/2.

When x = -1 , y = 4 so using the slope intercept form of a line

y = mx + b

4 = -3/2 * -1 + b where b = the y-intercept.

4 = 3/2 + b

b = 4 - 3/2 = 5/2.

The equation is y = -3/2 x + 5/2.

3 0

3 years ago

Simplify this expression.<br> <img src="https://tex.z-dn.net/?f=2%5Csqrt5%2813%2B%5Csqrt2%29" id="TexFormula1" title="2\sqrt5(13

andreyandreev [35.5K]

Step-by-step explanation:

everything can be found in the picture

5 0

2 years ago

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Darlene is adopting a pet. she can choose from 8 kittens and 6 puppies.How many ways can she choose a pet to adopt

juin [17]

14 cause shes only getting 1 pet and there are 14 animals in total

7 0

2 years ago

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A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

3 years ago