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3 years ago

10

Prove Tan x - 1/Tan x + 1 = 1 - cot x/1 + cot x

1 answer:

klasskru [66]3 years ago

5 0

$\dfrac{\tan x-1}{\tan x+1}=\dfrac{\dfrac{\sin x}{\cos x}-1}{\dfrac{\sin x}{\cos x}+1}=\dfrac{\sin x-\cos x}{\sin x+\cos x}=\dfrac{1-\dfrac{\cos x}{\sin x}}{1+\dfrac{\cos x}{\sin x}}=\dfrac{1-\cot x}{1+\cot x}$

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How much should you put in an investment paying a simple interest rate of 5% if you needed $4000 in eighteen mont

Eddi Din [679]

now, there are 12 months in a year, so 18 months is really 18/12 of a year, thus

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2 years ago

A ____ is a term with a number part but no variable. (WILL GIVE BRAINLIEST) (❁´◡`❁)

Margaret [11]

Answer: it’s a Constant!

Step-by-step explanation:

4 0

2 years ago

The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt

Marizza181 [45]

Answer:

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

$L=w+2$

now, we can find area

$A=L\times W$

now, we can plug it

$A=(w+2)\times w$

$A=w^2+2w$

we are given area =6

so, we can set it equal

and then we can solve for w

$w^2+2w=6$

$w^2+2w-6=0$

we can use quadratic formula

$ax^2+bx+c=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a,b and c

a=1 , b=2 , c=-6

$w=\frac{-2\pm \sqrt{2^2-4\cdot \:1\left(-6\right)}}{2\cdot \:1}$

$w=-1+\sqrt{7},\:w=-1-\sqrt{7}$

we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

7 0

3 years ago

Answer the question.

san4es73 [151]

Alright so
5^4m = 5^12
cancel the bases
4m=12
divide by 4
m=3

6 0

3 years ago