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matrenka [14]
3 years ago
13

susan is driving to mount shasta .on her map she is a distance of 7 inches away .the scale of the map is 1/2 inch=50 miles.how f

ar must susan travel to reach her destination?
Mathematics
1 answer:
DochEvi [55]3 years ago
6 0

Answer:

700 miles

Step-by-step explanation:

Given:

Scale of the map is \frac{1}{2}\textrm{ in}=50\textrm{ mi}

∴ 1\textrm{ in}= \frac{50}{\frac{1}{2}}=50\times 2=100\textrm{ mi}

Distance of Susan from mount Shasha on the map is 7 inch.

Therefore, Number of miles = 7\times 100=700\textrm{ mi}

Hence, Susan must travel 700 miles to reach her destination.

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A bakery sells pie slices that are 1/6 of a pie. If they made 18 pies today.How many slices of pie will they have?
Lera25 [3.4K]

Answer:

108 slices

Step-by-step explanation:

One pie is 6 slices so 6*18 is equal to 108

4 0
2 years ago
What is the slope of the line passing through the points (1, –5) and (4, 1)?
Naddik [55]
The slope is a 2
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3 0
3 years ago
Terri played 70 tournament chess games during the school year and won 49 of them. What is her win-to-loss ratio?
Scilla [17]

Alright so the answer would be letter B, because

win-to-loss

49 to 21 (You can determine her losses by subtracted the number of wins from her total number of games played)

Now you must simplify your answer

7 is the greatest common factor (GCF) of both 49 and 21

Now divide both 49 and 21 by 7 to get

7 to 3

7 0
3 years ago
How do you do this problem?
faust18 [17]

The volume of the original cylinder is

... V = π·r²·h

For r=1 and h=1, this is

... V = π·1²·1 = π

For the new cylinder, the volume is 1.089 times that amount.

... V = 1.089π = π·1.1²·(1-k)

... 1.089/1.21 = 1-k

... k = 1 - 1.089/1.21 = 1 - 0.9 = 0.1 = 10%

The appropriate choice is (B) 10.

7 0
3 years ago
Read 2 more answers
Which statement is true about point F? a.F is the midpoint of AA' because bisects AA'. b.F is the midpoint of EG because AA' bis
Dimas [21]

Answer:

The correct option is;

a. F is the midpoint of \overline{AA'} because line \overline{EG} bisects \overline{AA'}

Step-by-step explanation:

Here, since we have that the triangle is reflected across EG therefore the location of the point F which is along EG bisects the line \overline{AA'} as the  dimensions of the line from A to F must be equal to the dimension of the line that extends from A' to F

Therefore the point F is the midpoint of \overline{AA'} because line \overline{EG} bisects \overline{AA'}.

7 0
3 years ago
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