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weqwewe [10]
4 years ago
6

Nancy decides to roll a die three times. What's the probability that she will roll all even numbers?

Mathematics
1 answer:
nignag [31]4 years ago
7 0

Answer:

  1/8

Step-by-step explanation:

The probability of rolling an even number on one roll is 3/6 = 1/2. Assuming the rolls are independent, the probability of rolling an even number 3 times is ...

  (1/2)(1/2)(1/2) = 1/8

The probability that Nancy rolls all even numbers in 3 rolls is 1/8.

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If angle QPS if you angle and M angle QPR equals 71° what is M angle RPS
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I DONT UNNUSTANDEH

Step-by-step explanation:

i dont think it is proper english.

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3 years ago
What is the period of y = 8 cos (5pie x + 3pie/2)-9<br> Give an exact value. Units
zzz [600]

\\ \rm\Rrightarrow y=Acos(Bx+C)+D

  • This is the general formula and the period is 2π/B

Now our given function

\\ \rm\Rrightarrow y=8cos\left(5\pi x+\dfrac{3\pi}{2}\right)-9

On comparing we get

  • A=8
  • B=5π
  • C=3π/2
  • D=-9

Period:-

\\ \rm\Rrightarrow \dfrac{2\pi}{B}

\\ \rm\Rrightarrow \dfrac{2\pi}{5\pi}

\\ \rm\Rrightarrow \dfrac{2}{5}

3 0
2 years ago
Read 2 more answers
36/78 as a fraction
muminat

Answer:

6/13

Step-by-step explanation:

36/78 simplified:

36/78 ---> 18/39 --->6/13

8 0
3 years ago
Which solution can be used to fill in both blanks in the table?
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Answer:

(6,7)

Step-by-step explanation:

6 0
3 years ago
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Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar
horsena [70]

Answer:

P(A) = \frac{1}{9}

P(B) = \frac{1}{3}

P(C) = \frac{1}{729}

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

P(M) = \frac{1}{3}.

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is P(A) = \frac{1}{9}. We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

So

P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}.

C. If the probability that two people have been hired on a specific day of the week is 3(\frac{1}{3}) ^ 2, then the probability that 7 people have been hired on the same day is:

P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}

D. The probability is \frac{1}{729}. This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0
3 years ago
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