If $4,000,000 is invested at 5% interest compounded continuously, how much
1 answer:
Answer:$13,925,161.81
Step-by-step explanation:
A=P(1+r/n)^nt
A=amount
P=Principal
R =rate in decimal
T=time
N=number of times compounded at period t
A=4000000(1+0.05/12)^12×25
=4000000(1.0041666)^300
=4000000(3.4812835183479)
=$13,925,161.81
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Hey there ! please refer to the attachment .
I hope its help you !
