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3 years ago

What is the answer to this question

Mathematics

2 answers:

ale4655 [162]3 years ago

5 0

Answer:

the answer is x+27

Sidana [21]3 years ago

4 0

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I'm a little confused on a question a have to do. It says, Alan has a map of Narniland on his kitchen table. A. How is the table

omeli [17]

<span>geometric plane says it extends infinitely outward in all directions and has no thickness. so that wouldn't fit a table so its pretty much what i just said</span>

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3 years ago

What is the maximum number of possible extreme values for the function f(x)=x^4+x^3-7x^2-x+6

notka56 [123]

A 4th degree polynomial will have at most 3 extreme values. Since the degree is even, there will be one global extreme, with possible multiplicity. The remainder, if any, will be local extremes that may be coincident with each other and/or the global extreme.

(The number of extremes corresponds to the degree of the derivative, which is 1 less than the degree of the polynomial.)

3 0

3 years ago

Read 2 more answers

Write the following equations in slope intercept form

Rus_ich [418]

Answer:

problem 1 2x+5y= 0

×=-1/2-5/2y

problem 2 y=1 3/7y y=-1.428571

7y=-10

problem 3 x=-7

problem 4 x-y=20

x=-20

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3 years ago

Express log2 64-log2 4 as a simple logarithm

Triss [41]

<span>Express log(2)64-log(2)4 as a single logarithm.
Simplify as possible.
Solution:

= log(2)[64/4]
= log(2)[16]
= 4
</span>

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2 years ago

A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these so

otez555 [7]

Answer: (0.132132, 0.274368)

Step-by-step explanation:

Given : A simple random sample of 123 people living in Gastown and finds that 25 have an annual income that is below the poverty line.

i.e. n= 123

$\hat{p}=\dfrac{25}{123}\approx0.203252$

Critical value for 95% confidence interval : $z_{\alpha/2}=1.96$

Confidence interval for population :

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}$

$0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}\\\\\0.203252\pm0.071118\\\\=(0.20325-0.071118,\ 0.203252+0.071118)\\\\=(0.132132,\ 0.274368)$

Hence, the 95% confidence interval for the true proportion of Gastown residents living below the poverty line : (0.132132, 0.274368)

5 0

3 years ago