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olganol [36]
3 years ago
5

Find the domain of y = 4 square root 4x + 2

Mathematics
1 answer:
kherson [118]3 years ago
3 0

Answer:

\Large \boxed{x\geq -\frac{1}{2}}

Step-by-step explanation:

The domain is all possible values for x.

y=4\sqrt{4x+2}

There are restrictions on the value of x.

A square root of a negative number is undefined.

The number in the square root has to be equal to 0 or be greater than 0.

4x+2\geq 0

Subtract 2 from both sides.

4x\geq -2

Divide both sides by 4.

\displaystyle x\geq -\frac{2}{4}

\displaystyle x\geq -\frac{1}{2}

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Solve by substitution. Show each step of your work.
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Substituting y= -5x+15 from first equation into second equation:

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3 years ago
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Tobeg says the equation 3x + 2y= 270 and y=4/5x + 20 intersect at the point (50,60) is this true how do you know
il63 [147K]

ANSWER

Yes it is very true


<u>EXPLANATION</u>

If the two equations intersect at (50,60) then this point must satisfy the two equations.


3x+2y=270---(1)

We substitute  (50,60)  in to erquation (1)


3(50)+2(60)=270


150+120=270

270=270




y=\frac{4}{5}x+20 ---(2)


We now substitute  (50,60)  in to erquation (2) also


60=\frac{4}{5}(50)+20


60=40+20


60=60


Since the point satisfy all the two equations, it is true that they intersect at (60,50)




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Step-by-step explanation:

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