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olganol [36]
3 years ago
5

Find the domain of y = 4 square root 4x + 2

Mathematics
1 answer:
kherson [118]3 years ago
3 0

Answer:

\Large \boxed{x\geq -\frac{1}{2}}

Step-by-step explanation:

The domain is all possible values for x.

y=4\sqrt{4x+2}

There are restrictions on the value of x.

A square root of a negative number is undefined.

The number in the square root has to be equal to 0 or be greater than 0.

4x+2\geq 0

Subtract 2 from both sides.

4x\geq -2

Divide both sides by 4.

\displaystyle x\geq -\frac{2}{4}

\displaystyle x\geq -\frac{1}{2}

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