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Slav-nsk [51]
3 years ago
5

A line has a slope of -1/2 and a y-intercept of -2. what is the x-intercept of the line?​

Mathematics
1 answer:
ElenaW [278]3 years ago
3 0

Answer:

-4

Step-by-step explanation:

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Rewrite the following sentence in the passive voice:
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Answer:

When the tourists came, the people of Zanzibar extended a warm welcome.​

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The probability that a traffic light will be green is 40%. If you pass through 3 lights on your way to the store, what is the pr
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Answer:

0.216

Step-by-step explanation:

If the probability of green, P(green) is 40%, the probability of red, P(red) is 60%.

The probability of a light being red is not affected by the colour of the previous light, so at each of the 3 lights, the probability of red is always 60%.

To find the probability that all three lights will be red, multiply the three probabilities together. (Convert them to decimals first).

0.6 x 0.6 x 0.6 = 0.216

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3 years ago
How many vertices are in a polyhedron with 6 triangular faces?
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I believe it will be 36 Im sorry if im wrong.
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What effect does the word snatch have on the reader?
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Step-by-step explanation:

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A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
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