Answer:
Hopes it helps
Step-by-step explanation:
The Quadratic Polynomial is
2 x² +x -4=0
Using the Determinant method to find the roots of this equation
For, the Quadratic equation , ax²+ b x+c=0
(b) x²+x=0
x × (x+1)=0
x=0 ∧ x+1=0
x=0 ∧ x= -1
You can look the problem in other way
the two Quadratic polynomials are
2 x²+x-4=0, ∧ x²+x=0
x²= -x
So, 2 x²+x-4=0,
→ -2 x+x-4=0
→ -x -4=0
→x= -4
∨
x² +x² +x-4=0
x²+0-4=0→→x²+x=0
→x²=4
x=√4
x=2 ∧ x=-2
As, you will put these values into the equation, you will find that these values does not satisfy both the equations.
So, there is no solution.
You can solve these two equation graphically also.
Answer:
x= y^2 -6y
Step-by-step explanation:
Formula:
x + 2(x+1) = 17
x + 2x + 2 = 17
3x + 2 = 17
3x = 15
x = 5
So, the answer is 5 and 6
Hope this helped!
this equation is not funcion.
Step-by-step explanation:
if u make a graph and u aline them with dots 2 or more dots will cross each other witch makes it not function:)
Your Answer should be True
