Answer:
no solutions
Step-by-step explanation:
10x+2y=42
5x+y=20
Multiply the second equation by -2 to use elimination
-2(5x+y)=20*-2
-10x -2y = -40
Add this to the first equation
10x+2y=42
-10x -2y = -40
--------------------------
0 = 2
This is never true. This means there are no solutions
Answer:
x = 55
Step-by-step explanation:
Draw a line parallel to the top and bottom parallel lines so this new line goes through the pointed end of x.
Draw another line parallel to the top and bottom lines through the pointy end of 45.
The bottom angle of the line through 45 is 15 degrees (alternate interior angles.
The top angle is 45 - 15 = 30
The bottom angle of the line going to x is 150 degrees. It and the 30 degree angle make 180. 30 + 150 = 180
One final observation The top angle of made by the line going through x is 180 - 25 = 155
What you have now is
155 + 150 + x = 360
305 + x = 360
x = 360 - 305
x = 55
Answer:
I'm pretty sure it's 4 sorry if I'm not right I'm not the best at this stuff either
Answer:
m=13
Step-by-step explanation:
Ok
l8ml=104
8m=104
⁻⁻⁻ ⁻⁻⁻
8 8
m=13
9514 1404 393
Answer:
Step-by-step explanation:
A graphing calculator answers these questions easily.
The ball achieves a maximum height of 40 ft, 1 second after it is thrown.
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The equation is usefully put into vertex form, as the vertex is the answer to the questions asked.
h(t) = -16(t^2 -2t) +24
h(t) = -16(t^2 -2t +1) +24 +16 . . . . . . complete the square
h(t) = -16(t -1)^2 +40 . . . . . . . . . vertex form
Compare this to the vertex form:
f(x) = a(x -h)^2 +k . . . . . . vertex (h, k); vertical stretch factor 'a'
We see the vertex of our height equation is ...
(h, k) = (1, 40)
The ball reaches a maximum height of 40 feet at t = 1 second after it is thrown.
