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3 years ago

Which line is parallel to 4y - 12x = 20

Mathematics

1 answer:

iren [92.7K]3 years ago

6 0

Your answer should be A. Y=3x-1

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Antonio uses a calculator to find 38 minus StartFraction 44 minus 16 over 4 EndFraction and gets a result of –10. Which statemen

frozen [14]

Answer:

The second statement is Correct.

Step-by-step explanation:

Consider the provided information.

It is given that Antonio uses a calculator to find $38-\frac{44-16}{4}$ and gets a result of –10.

$38-\frac{44-16}{4}=38-\frac{28}{4}$

$=38-7$

$=31$

So, the first statement is incorrect.

2nd statement: Antonio found the answer for $38-44-\frac{16}{4}$

$38-44-\frac{16}{4}=-6-4$

$38-44-\frac{16}{4}=-10$

The second statement is Correct.

Third statement: Antonio found the answer for $\frac{38-44-16}{4}$

$\frac{38-44-16}{4}=-5.5$

So, the third statement is incorrect.

Fourth statement: Antonio found the answer for $38+\frac{44-16}{4}$

$38+\frac{44-16}{4}=38+7$

$38+\frac{44-16}{4}=45$

So, the fourth statement is incorrect.

Hence, the second statement is Correct.

5 0

3 years ago

Read 2 more answers

The average cost for a gallon of gasoline increased from $2.56 one year to $3.18 the next year. What is the percent of increase,

Kitty [74]

From 2.56 to 3.18; 3.18-2.56=0.62 increased
so if 2.56 represented 100%
0.62 represents ? %
cross multiply
?%= 0.62·100/2.56=24.21875 which rounded to the nearest whole is 24%
Answer is B).

7 0

3 years ago

Read 2 more answers

How do you multiply mixed numbers and then estimate them

Vadim26 [7]

You do 5 multiple by 2 + 2. 4 multiple by 3 + 3. 12 multiple by 15 is 180

5 0

3 years ago

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

4 0

2 years ago

6 divided by 9.51 plz help me

astra-53 [7]

Answer:

0.63091482649

Step-by-step explanation:

3 0

3 years ago