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shutvik [7]
3 years ago
14

Which line is parallel to 4y - 12x = 20

Mathematics
1 answer:
iren [92.7K]3 years ago
6 0
Your answer should be A. Y=3x-1
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Antonio uses a calculator to find 38 minus StartFraction 44 minus 16 over 4 EndFraction and gets a result of –10. Which statemen
frozen [14]

Answer:

The second statement is Correct.

Step-by-step explanation:

Consider the provided information.

It is given that Antonio uses a calculator to find 38-\frac{44-16}{4} and gets a result of –10.

38-\frac{44-16}{4}=38-\frac{28}{4}

=38-7

=31

So, the first statement is incorrect.

2nd statement: Antonio found the answer for 38-44-\frac{16}{4}

38-44-\frac{16}{4}=-6-4

38-44-\frac{16}{4}=-10

The second statement is Correct.

Third statement: Antonio found the answer for \frac{38-44-16}{4}

\frac{38-44-16}{4}=-5.5

So, the third statement is incorrect.

Fourth statement: Antonio found the answer for 38+\frac{44-16}{4}

38+\frac{44-16}{4}=38+7

38+\frac{44-16}{4}=45

So, the fourth statement is incorrect.

Hence, the second statement is Correct.

5 0
3 years ago
Read 2 more answers
The average cost for a gallon of gasoline increased from $2.56 one year to $3.18 the next year. What is the percent of increase,
Kitty [74]
From 2.56 to 3.18; 3.18-2.56=0.62 increased 
so if 2.56 represented 100%
       0.62 represents     ? %
cross multiply 
?%= 0.62·100/2.56=24.21875 which rounded to the nearest whole is 24%
Answer is B).
7 0
3 years ago
Read 2 more answers
How do you multiply mixed numbers and then estimate them
Vadim26 [7]
You do 5 multiple by 2 + 2. 4 multiple by 3 + 3. 12 multiple by 15 is 180
5 0
3 years ago
Find the following integral
ololo11 [35]

There's nothing preventing us from computing one integral at a time:

\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2

\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2

\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx

Expand the integrand completely:

x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x

Then

\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}

4 0
2 years ago
6 divided by 9.51 plz help me
astra-53 [7]

Answer:

0.63091482649

Step-by-step explanation:

3 0
3 years ago
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