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AleksandrR [38]
3 years ago
5

an architect creates a scale model of a building with a scale of 3 inches = 11 feet. if the actual width of the building is 121

feet, what is the width of the scale model
Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0

Answer:

the awnser is 3 because 3 * 11 = 33 then 121 divided by 33 = 3

Step-by-step explanation:

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Can someone help? i cannot get this question right
Blizzard [7]

Answer:

  see below

Step-by-step explanation:

The function f(x) is the absolute value function scaled vertically and shifted up. Neither of those transformations affects the interval on which it is increasing. The absolute value function increases for x > 0. (It is neither increasing nor decreasing at x=0.)

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The function g(x) is a parabola that opens downward. Consequently, it is increasing for all values of x to the left of its vertex (or line of symmetry). That line of symmetry can be found as ...

  x = -b/(2a) = -(8)/(2·(-1)) = 4

So g(x) is increasing from -∞ to 4, but at x=4 is neither increasing nor decreasing.

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Then the interval on which both functions are increasing is ...

  {x > 0} ∩ {x < 4} = {0 < x < 4}

This will be graphed as a line between 0 and 4 with open circles at each end.

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The second attachment shows the two functions so you can see where their slopes are positive.

5 0
3 years ago
What is the degree of 7x + 1?
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

degree 1

3 0
3 years ago
Ronald measured a house and its lot and made a scale drawing. The front patio, which is 14 meters wide in real life, is 7 millim
zhannawk [14.2K]

Answer:

2 metre= 1millimetre

Step-by-step explanation:

From the measurement of the house The front patio, is 14 meters wide in real life, is 7 millimeters wide in the drawing

Real life= 14 meters

Drawing= 7 millimeters,

The scale he used is 2 metre= 1millimetre

Which means he magnify the drawing by scale of 2 metre to get the real life structure.

✓Let us clarify it

14 meters = 7 millimeters

2 metre= x millimeter

If we cross multiply

7 millimeters× 2 metre= 14 metre × X millimeters

Make X subject of the formula we have

X= 1millimetres

3 0
3 years ago
Isaiah decides to launch a model rocket to demonstrate parabolic motion. Given x stands for time and y stands for height in feet
mina [271]

The parabolic motion is an illustration of a quadratic function

The equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31

<h3>How to model the function?</h3>

Given that:

x stands for time and y stands for height in feet

So, we have the following coordinate points

(x,y) = (5,0), (11,0) and (10,80)

A parabolic motion is represented as:

y =ax^2 + bx + c

At (5,0), we have:

25a + 5b + c = 0

c= -25a - 5b

At (11,0), we have:

121a + 11b + c = 0

Substitute c= -25a - 5b

121a + 11b -25a - 5b = 0

Simpify

96a + 6b = 0

At (10,80), we have:

100a + 10b + c = 80

Substitute c= -25a - 5b

100a + 10b - 25a -5b = 80

75a -5b = 80

Divide through by 5

15a -b = 16

Make b the subject

b = 15a + 16

Substitute b = 15a + 16 in 96a + 6b = 0

96a + 6(15a + 16) = 0

Expand

96a + 90a + 96 = 0

This gives

186a = -96

Solve for a

a = -16/31

Recall that:

b = 15a + 16

So, we have:

b = -15 * 16/31 + 16

b =-240/31 + 16

Take LCM

b =(-240 + 31 * 16)/31

[tex]b =256/31

Also, we have:

c= -25a - 5b

This gives

c= 25*16/31 - 5 * 256/31

Take LCM

c= -880/31

Recall that:

y =ax^2 + bx + c

This gives

y = -16/31x^2 + 256/31x - 880/31

Hence, the equation that models that path of the rocket is y = -16/31x^2 + 256/31x - 880/31

Read more about parabolic motion at:

brainly.com/question/1130127

7 0
2 years ago
The length from one point to another that is a portion of the curve of the circle is called:
Tom [10]

Answer:

The length from one point to another that is a portion of the curve of the circle is called <u>arc</u>

5 0
2 years ago
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