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3 years ago

Which of the following best describes the end behavior of y=x^2 -bx +c as x approaches either positive or negative infinity?

1 answer:

7 0

As x approaches either positive or negative infinity, y will approach positive infinity.
This is because x^2 will grow large much quicker than b*x, so it has more importance. So when considering the limit, we can imagine that the equation looks like this:
y = x^2
This equation will go to infinity for x approaching both negative and positive infinity.

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What is the difference?

Serhud [2]

Answer:

The option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

The difference of the given expression is

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Step-by-step explanation:

Given expression is $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

To find the difference of the given expression as below :

$\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-9)})-({\frac{x+1}{x^2-9})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-3^2)})-({\frac{x+1}{x^2-3^2})$

$=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x-3)(x+3)})-({\frac{x+1}{(x-3)(x+3)})$

( using the formula $a^2-b^2=(a+b)(a-b)$ )

$=\frac{2x+5(x+3)-(3x+5)-x(x+1)}{x(x-3)(x+3)}$

$=\frac{2x^2+6x+5x+15-3x-5-x^2-x}{x(x-3)(x+3)}$ (adding the like terms)

$=\frac{x^2+7x+10}{x(x^2-9)}$ ( by factoring the quadratic polynomial )

$=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore $\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}$

Therefore the difference of the given expression is

$\frac{(x+5)(x+2)}{x^3-9x}$

Therefore option $\frac{(x+5)(x+2)}{x^3-9x}$ is correct

8 0

3 years ago

A 4×4 square is divided into 16 cells as shown. Divide the square into two congruent (identical) parts by cutting only along the

VladimirAG [237]

Answer:cut it in half, / that way and — that way, cut it straight down, |,

Step-by-step explanation: math

4 0

3 years ago

Read 2 more answers

Help me please and thank you

allochka39001 [22]

Answer:

Option C is correct

Step-by-step explanation:

$log( {10}^{3} )$

Use logarithm rules to move 3 out of the exponent.

$3 \: log \: (10)$

Logarithm base 10 of 10 is 1.

$3×1$

Multiply 3 by 1.

$3$

<h3>Hope it is helpful....</h3>

6 0

3 years ago

Read 2 more answers

9^2 times 9^-6 exponential form

Scrat [10]

The result of the expression in exponential form is 9^-4

<h3>Product of exponents</h3>

Given the expression below

$9^2 \times 9^{-6}$

According the product law, since the base are equal, we will add the exponent to have:

$9^2 \times 9^{-6}=9^{-6+2}\\9^2 \times 9^{-6} = 9^{-4}$

Hence the result of the expression in exponential form is 9^-4

Learn more on exponents here; brainly.com/question/11975096

#SPJ1

7 0

2 years ago

To the nearest hundredth, what is the distance between point (-6, -1) and point (4, 3)?

vagabundo [1.1K]

Use the distance formula and simply substitute in the corresponding orders pairs.

Distance = √(x2 - x1)² + (y2 - y1)²

Distance = √(4 - (-6))² + (3 - (-1))²

Distance = √(4 + 6)² + (3 + 1)²

Distance = √(10)² + (4)²

Distance = √100 + 16

Distance = √116

Distance = 10.7703296143

Round to the nearest hundredth!

Distance ≈ 10.77

5 0

3 years ago

Read 2 more answers