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Alja [10]
2 years ago
8

9^2 times 9^-6 exponential form

Mathematics
1 answer:
Scrat [10]2 years ago
7 0

The result of the expression in exponential form is 9^-4

<h3>Product of exponents</h3>

Given the expression below

9^2 \times 9^{-6}

According the product law, since the base are equal, we will add the exponent to have:

9^2 \times 9^{-6}=9^{-6+2}\\9^2 \times 9^{-6} = 9^{-4}

Hence the result of the expression in exponential form is 9^-4

Learn more on exponents here; brainly.com/question/11975096

#SPJ1

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Find the height of the pyramid. Please help ASAP.
LekaFEV [45]
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4 0
4 years ago
A certain unsavory bar for poker-playing dogs is attended by only two types of dogs: "good dogs" and "bad dogs." For a randomly
SVETLANKA909090 [29]

Answer: The required probability is 0.1923.

Step-by-step explanation:

Since we have given that

Probability that it's a good dog = 0.4

Probability that it's a bad dog = 1-0.4 = 0.6

Probability that the dog smokes given that its a bad dog = 0.7

Probability that it smokes given that its a good dog = 0.25

According to question, probability of smoking pipe would be

P(good).P(Smoking pipe|good)+P(bad).P(smoking pipe|bad)

0.4\times 0.25+0.6\times 0.7\\\\=0.1+0.42\\\\=0.52

So, Probability of getting a good dog given that it is smoking pipe is given by

\dfrac{P(good).P(smoking\ pipe|good)}{P(smoking\ pipe)}\\\\=\dfrac{0.4\times 0.25}{0.52}\\\\=\dfrac{0.1}{0.52}\\\\=0.1923

Hence, the required probability is 0.1923.

3 0
3 years ago
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Need help pls! Answer asap
Lostsunrise [7]
1. 130°

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2. 50°

A straight line is 180°, and 180 - 130 = 50.
7 0
3 years ago
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There are 99 males and 121 females participating in a marathon. What participants are females?
notsponge [240]

Answer:

121..??

Step-by-step explanation:

4 0
3 years ago
Can some one please help me <br> will give 94 points for it
NNADVOKAT [17]
You can solve this by using "similar triangles".

In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.

You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
\frac{AC}{BC} =  \frac{DF}{EF}
Substitute for the values of AC, BC, DF and EF:
\frac{x}{4}  =  \frac{11}{8}  \\  \\ 8x = 4 \times 11 \\  \\ x =  \frac{44}{8}
x = 5.5 \: units
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
\frac{AB}{BC}  =  \frac{DE}{EF}
Substitute for the values and solve:
\frac{3}{4}  =  \frac{y}{8}
4y = 24 \\  \\ y = 6 \: units

We have the value x to be 5.5 units and y to be 6 units.

7 0
3 years ago
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