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Dima020 [189]
3 years ago
14

Daniela sells handmade purses for $22. She

Mathematics
1 answer:
Evgen [1.6K]3 years ago
5 0

Answer:

6 purses

Step-by-step explanation

1. Subtract 71 from 161 as that's how much Daniela needs to make to have 161, which is 90

2. Divide 15 by 90 as 15 is the profit, so the answer would be the amount of purses she needs to sell, then you get 6

Check

6 times 15, 90

71 + 90 = 161

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Determine the sign of the some of negative 8 + 11
AVprozaik [17]

Answer:

positive 3

Step-by-step explanation:

-8 + 11 is 3. the other way you can think of it is by subtracting 8 from 11.

8 0
3 years ago
Read 2 more answers
g In R simulate a sample of size 20 from a normal distribution with mean µ = 50 and standard deviation σ = 6. Hint: Use rnorm(20
Illusion [34]

Answer:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

For this case first we need to create the sample of size 20 for the following distribution:

X\sim N(\mu = 50, \sigma =6)

And we can use the following code: rnorm(20,50,6) and we got this output:

> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

> mean(a)

[1] 50.72451

> sqrt(var(a))

[1] 7.470221

5 0
3 years ago
Mr Burns wants to buy every student in year 11 a doughnut
dusya [7]

26*5 is 130

He'll have ten left over if each student in year 11 has one :) Hope this helps!

6 0
3 years ago
Read 2 more answers
Which point below is a solution to the equation y = 2x + 3?
Anastasy [175]

Answer:

C (37, 77)

Step-by-step explanation:

<h3>Option A:</h3>

291=2(145)+3\\\\291=290+3\\\\\boxed{291\neq 293}

Option A is not a solution.

<h3>Option B:</h3>

163=2(78)+3\\\\163=156+3\\\\\boxed{163\neq 159}

Option B is not a solution.

<h3>Option C:</h3>

77=2(37)+3\\\\77=74+3\\\\\boxed{77=77}

Option C is a solution.

Hope this helps.

6 0
3 years ago
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An English class consists of twenty students, and four are to be chosen to give speeches in a school competition.
NemiM [27]
A)If the order of the speakers is important, we have 20x19x18x17, or 116,280 different options.
b) If order is not important, then we have 20 choose 4, or 4845 different slates. ☺☺☺☺
4 0
3 years ago
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