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Blizzard [7]
3 years ago
11

the cubic polynomial f(x) is such that the coefficient of x cube is -1 and the roots of the equation f(x)=0 are 1, 2 & k.Giv

en that f(x) has a remainder of 8 when divided by x-3, find the value of k.

Mathematics
1 answer:
77julia77 [94]3 years ago
3 0
The polynomial function is a cubic polynomial function with a general equation of y = ax^3 + bx^2 + cx + d. a is given to be -1. roots make y = 0

when x = 1
y = -1(1) + b + c + d = -1 +b+c+d = 0
when x = 2
y = -1*8 + 4b + 2c + d = -8 + 4b+c+d = 0
when x =k 
y = -k^3 + k^2b + kc + d = 0

when x = 3, y =8
8 = -27 + 9b + 3c + d

<span>b=7/3 , c=23/3 , d=−9
</span>k1<span> = 9.3556</span>
k2<span> = -2.71051</span>
k3<span> = 0.35491</span>
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46.2 × 10–2 = A. 0.0462 B. 0.462 C. 4.62 D. 462
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46.2*(10-2)
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In general, when a number written in scientific notation includes a positive exponent, the magnitude of the number is __________
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when a number written in scientific notation includes a positive exponent, the magnitude of the number is <span>greater than one</span>
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I need help on these what is 5=g-8
Levart [38]
The answer is g=13 I hope this helped
7 0
3 years ago
Decrease 117 kg in the ratio 10:13​
Lisa [10]

Answer:

90kg

Step-by-step explanation:

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8 0
2 years ago
2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18
anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

4 0
3 years ago
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