Lesson 1 Homework

Mathematics

1 answer:

Nonamiya [84]2 years ago

5 0

128

This question requires us to solve an infinite GP

As we can see the first unit is 16 wide, then 8, then 4 and so on; this can be written as

$64(1,0.5,0.25,0.125,....$ $\infinity$ ∞ $)$ (64 used as 16*4 = 64 is the area of the first rectangle)

We have $S$ ∞ $=a/(1-r)$ where a is the first term and r is the common ratio of the GP for summing an infinite GP.

here we have

$a=64 \\ r=0.5$

Therefore

$S$ ∞ $=\frac{64}{1-0.5} \\\\=\frac{64}{0.5} \\\\=128$

Learn more about GP here

brainly.com/question/16954106

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ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

<h3>What are Congruent Triangles?</h3>

Congruent triangles are triangles whose corresponding sides are congruent to each other.

The hypotenuse of triangle JKL(KL = 10) is congruent to a leg of triangle XYZ (YX = 10). This implies that they cannot be congruent triangles.

Therefore, ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

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