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Answer:
131 packets
Explanation:
Given
W (link ) =0.5 M bits, and Ping packets ( P ) = 500bytes
To flood a target organization that has a bandwidth of W bits using a packet Mbits, you will require a W / P packet
P ( required ) = 500 * 8 = 4000 bits
therefore the W /P packet is calculated as
= 0.5 M bits / 4000 bits
given that : 1 M bits = 1,048,576 bits
0.5 M bits / 4000 bits= 131.07
hence approximately 131 packets/ sec is required to flood the target organization
list1 = [12500, 35000, 12000, 40000, 55000,60000]
print(sum(list1)/len(list1))
We take the sum of all the elements in the list and divide the sum by the quantity of the elements. You can put however many elements in this list and you'll always get the average using the algorithm above.
