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AURORKA [14]
3 years ago
13

What the answer to this

Mathematics
1 answer:
Blababa [14]3 years ago
5 0
I am pretty sure the answer is A because the graph is a cubic function
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A ________ is a whole number that divides another whole number with a remainder of 0
Brut [27]

It's a factor. This concept is widely used throughout algebra, and you'll probably bump into it through the end of high school and beyond.

A common use is expressing a term in <em>prime factorization</em>, or reducing a number to its most base parts- primes. For example:

20 = 4 * 5 = 2 * 2 * 5

Of course, a number like 13 which is already prime is made up of itself and 1. <em>Factors do not have to be primes.</em> 20 is also reducible through combinations of 1, 2, 4, 5, 10, and 20. Prime factorization is just a handy example.

Basically, factors multiply with each other to create other numbers, and numbers can be reduced down to their factors.

8 0
4 years ago
NEED HELP ASAP WILL MARK BRAINLIEST
dsp73

Answer:

n xa xBizvz oh de obc di IV x in bhi de vo CW in uw ICQ bhi ceci CQox vo s jb jiiiijjj in bh hhxhcbjjdJ0d hi sqbjzjksjsjs bv vh jb fb obc sa in hi few

8 0
3 years ago
Could I have help with this proof
pychu [463]

Answer:

Step-by-step explanation:

7 0
4 years ago
When a function is evaluated with a zero, what does it represent?
Gre4nikov [31]
We know that
the points where the graph of the function crosses the y-axis is when <span>a function is evaluated with a zero, these points represent the y-intercept of the function
</span>
therefore
the answer is
Represent the y-intercept of the function
4 0
3 years ago
Determine the general solution of:<br><br> sin 3x - sin x = cos2x
SpyIntel [72]
Sin³ x-sin x=cos ² x

we know that:
sin²x + cos²x=1  ⇒cos²x=1-sin²x
Therefore:

sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0

sin³x=z

z³+z²-z-1=0

we divide by Ruffini method:
              1     1     -1     -1
        1           1      2      1                z=1
-------------------------------------
              1     2      1      0
       -1         -1      -1                       z=-1
--------------------------------------
              1     1       0                       z=-1

Therefore; the solutions are z=-1 and z=1

The solutions are:
if z=-1, then
sin x=-1   ⇒x= arcsin -1=π+2kπ    (180º+360ºK)   K∈Z


if z=1, then
sin x=1   ⇒ x=arcsin 1=π/2 + 2kπ   (90º+360ºK)   k∈Z

π/2 + 2kπ    U   π+2Kπ=π/2+kπ     k∈Z    ≈(90º+180ºK)

Answer: π/2 + Kπ    or     90º+180ºK          K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
6 0
3 years ago
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