Answer:
54
Step-by-step explanation:
I think what you mean is y = 12, so I'll just go off that. So we substitute 12 for y and we get 4*12 + 6. Then we multiply. 48 + 6 and we get 54! I hope this helped and please mark brainliest!
Answer:
25
Step-by-step explanation:
it's so easy to get to know
Answer:
No.
Step-by-step explanation:
Jason, or "Her" is not correct.
Mark brainliest please and thank you
Answer:
a) The value of A = 2
b) The value of 
Step-by-step explanation:
a)
Given that:
X should be the random variable that assumes only positive integer values.
The probability function;
for some constant A and n ≥ 1.
Then, let ![\sum \limits ^{\infty}_{n =1} P[X =n] = 1](https://tex.z-dn.net/?f=%5Csum%20%5Climits%20%5E%7B%5Cinfty%7D_%7Bn%20%3D1%7D%20P%5BX%20%3Dn%5D%20%3D%201)
This implies that:




A = 2
Thus, the value of A = 2
b)
Suppose X represents a e constant A (n> 1). Find A.
b) Let X be a continuous random variable that can assume values between 0 and 3
Then, the density function of x is:

where; B is constant.
Then, using the property of the probability density function:

Taking the integral, we have:
![B \Big [\dfrac{x^3}{3} +x \Big ]^3_0 = 1](https://tex.z-dn.net/?f=B%20%5CBig%20%5B%5Cdfrac%7Bx%5E3%7D%7B3%7D%20%2Bx%20%5CBig%20%5D%5E3_0%20%3D%201)
![B \Big [\dfrac{3^3}{3} +3 \Big ]= 1](https://tex.z-dn.net/?f=B%20%5CBig%20%5B%5Cdfrac%7B3%5E3%7D%7B3%7D%20%2B3%20%5CBig%20%5D%3D%201)
![B \Big [\dfrac{27}{3} +3 \Big ] = 1](https://tex.z-dn.net/?f=B%20%5CBig%20%5B%5Cdfrac%7B27%7D%7B3%7D%20%2B3%20%5CBig%20%5D%20%3D%201)
B [ 9 +3 ] = 1
B [ 12 ] = 1
Divide both sides by 12

Answer:
x=11
Step-by-step explanation:
You have to isolate the x term; to do this you subtract 13 from the x+13 and the 24. By subtracting 13 from 13, it cancels out the 13 and 24-13=11