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3 years ago

Choose all of the points that are solutions to y = 3x + 2 / 2x - 1.

Mathematics

2 answers:

jolli1 [7]3 years ago

6 0

Answer:

its abfg

Step-by-step explanation:

Katen [24]3 years ago

4 0

Answer:

a d f g

Step-by-step explanation:

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Each edge of a cube is 1.5 cm in length. what is the surface area of the cube

Softa [21]

Answer:

The answer is 13.5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A statistician finds that the population P of a small developing country has been increasing at a rate of 3.65% annually. In 200

iren [92.7K]

Answer:

15.035 years

Step-by-step explanation:

The exponential function to calculate population growth is

P(t) = Poe^kt

P(t) = Population size after t years = 3.6 million

Po = Initial population size = 2.1 million

k = growth rate = 3.65% = 0.0365

t = time in years = ???

Hence:

3600000 = 2100000 × e ^0.0365t

Divide both sides by 2100000

3600000/2100000 = e^0.0365t

1.7142857143 = e^0.0365t

Find the log of both sides

Log 1.7142857143 = log (e^0.0365t)

Log 1.7142857143 /Log 0.0365 = t

t = 15.035 years

5 0

3 years ago

The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,

Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

If the mean number of arrivals is 10

This means that $\mu = 10$

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347$

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is $P(X \leq 10)$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045$

$P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045$

$P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023$

$P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076$

$P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189$

$P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378$

$P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631$

$P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901$

$P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126$

$P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251$

$P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251$

$P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831$

58.31% probability that there are no more than 10 arrivals.

8 0

3 years ago

Plz plz plz help meeee

Lina20 [59]

4.5/5 = 9/10

252= 9/10

252 divided by 9 = 28

0.5.= 28

5 = 252+ 28

5= 280

6 0

4 years ago

Line d has a slope of –7 4 . Line e is perpendicular to d . What is the slope of line e ? Simplify your answer and write it as a

Anna [14]

Answer:

4/7

Step-by-step explanation:

If the slope of line d is -7/4, then the slope of a perpendicular is 4/7.

Given a slope, to find the slope of a perpendicular, flip the fraction and change the sign.

Flip -7/4 to get -4/7. Then change the sign of -4/7 to get 4/7.

Answer: 4/7

4 0

3 years ago