84 is your awnser if i helped i hope im in fourth grade so dont judge
Answer:
89.1° or -1.4°
Step-by-step explanation:
1. Location:
You are on the Mont-Saint-Jean escarpment, near the Belgian town of Waterloo.
The French troops are about 50 m below you and 1.2 km distant.
2. Finding the firing angle
Data:
R = 1200 m
u = 600 m/s
h = -50 m (the height of the target)
a = 9.8 m/s²
We have two conditions.
Horizontal distance
(1) 1200 = 600t cosθ
Vertical distance
(2) -50 = 600t sinθ - 4.9t²
Divide each side of (1) by 600cosθ.

Substitute (3) into (2)

Recall that
(5) sec²θ = 1/cos²θ = tan²θ + 1
Substitute (5) into (4)

Set up a quadratic equation

Solve for θ
Use the quadratic formula.
tanθ = 61.249 or -0.025
θ = arctan(61.249) = 89.1° or
θ = arctan(-0.025) = -1.4°
Answer:
1/2
Step-by-step explanation:
Anything with an exponent of 1 is itself.
Answer:
A = 3.706 square meters
Step-by-step explanation:
the length of a cube has equal side.
therefore, the volume of a cube is given by S³
V = S³ = 7.14
where S is the length of a side
the surface area of a cube is = 6S²
where the area a aside is calculated, then it is multiply by 6.
if S³ = 7.14
S = ∛(7.14) = 1.925 m
What is the cross-sectional area that is parallel to one of its faces?
this is saying we should calculate for the cross-sectional area of one face. All faces in a cube is equal and parallel to each other.
the crossectional area of one side of a cube is = S² = 1.925² = 3.706 square meters
A = 3.706 square meters