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3 years ago

Please I need help with these 3 questions with explanation. See attached below.

Mathematics

1 answer:

amm18123 years ago

7 0

Answer:

18. compound interest

19. simple interest

20. simple interest

Step-by-step explanation:

For these problems, the initial balance is irrelevant. All that matters is the multiplier of that balance. For simple interest at rate r for t years, the multiplier is ...

simple interest multiplier = (1 +rt)

For interest compounded annually, the multiplier of the initial balance is ...

compound interest multiplier = (1 +r)^t

A spreadsheet can do the computations for you.

___

As an example of the computations involved, consider problem 19:

simple interest multiplier = 1 + 0.13·6 = 1.78

compound interest multiplier = 1.10^6 = 1.771561

The latter is less than the former, so the simple interest account will have the (slightly) greater balance at the end of 6 years.

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When we have a given function, y = f(x), the general way of graphing the function is finding a lot of coordinate pairs (x, f(x)) and graphing them in a coordinate axis, and then connect them.

So here we have:

p(x) = 2x^(3)+7x^(2)-3x-18

Just let's find the value of p(x) for different values of x, and let's do it.

p(0) = 2*0^(3)+7*0^(2)-3*0-18 = -18

Then the point (0, -18) belongs to the graph

p(1) = 2*1^(3)+7*1^(2)-3*1-18 = 2 + 7 - 3 - 18 = -12

then the point (1, - 12) belongs to the graph.

p(-1) = 2*(-1)^(3)+7*(-1)^(2)-3*(-1)-18 = -2 + 7 + 3 - 18 = -10

then the point (-1, -10) belongs to the graph:

p(2) = 2*2^(3)+7*2^(2)-3*2-18 = 16 + 28 - 6 - 18 = 20

Then the point (2, 20) belongs to the graph

p(-2) = 2*(-2)^(3)+7*(-2)^(2)-3*(-2)-18 = -16 + 28 + 6 - 18 = 0

Then the point (-2, 0) belongs to the graph.

p(-3) = 2*(-3)^(3)+7*(-3)^(2)-3*(-3)-18 = -54 + 63 + 9 - 18 = 0

Then the point (-3, 0) belongs to the graph.

Now that we have 6 points we can graph them and try to connect them.

We also know that this is a cubic polynomial, so we can expect that it changes its direction two times (no more than that) then knowing that we can estimate a shape for the graph, and you will obtain something like the graph of the image below, where I just connected the known points.