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MatroZZZ [7]
3 years ago
13

Please I need help with these 3 questions with explanation. See attached below.

Mathematics
1 answer:
amm18123 years ago
7 0

Answer:

  18. compound interest

  19. simple interest

  20. simple interest

Step-by-step explanation:

For these problems, the initial balance is irrelevant. All that matters is the multiplier of that balance. For simple interest at rate r for t years, the multiplier is ...

  simple interest multiplier = (1 +rt)

For interest compounded annually, the multiplier of the initial balance is ...

  compound interest multiplier = (1 +r)^t

A spreadsheet can do the computations for you.

___

As an example of the computations involved, consider problem 19:

  simple interest multiplier = 1 + 0.13·6 = 1.78

  compound interest multiplier = 1.10^6 = 1.771561

The latter is less than the former, so the simple interest account will have the (slightly) greater balance at the end of 6 years.

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Jackson rides his bike from his home for 30 minutes at a fast pace. He stops to rest for 20 minutes, and then continues riding i
Dimas [21]

Answer:

For the first 30 minutes, we will have a line with a given steepness, this will represent the 30 minutes riding at a fast pace.

Then he stops for 20 minutes, we will represent this with a constant line.

Then he again moves for another 30 minutes, but with a slower pace than in the first 30 minutes, then this line will be less steep than the first line.

A sketch of this situation can be seen below.

5 0
3 years ago
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
2 years ago
WILL MARK BRAINLIEST!!!! PLZ HELP!!!! Using the two-way table, what percentage of the students that like to travel out of state
grigory [225]

Answer:

  41%

Step-by-step explanation:

The table shows that 36 of the 88 students that like traveling out of state do not like camping. That percentage is ...

  36/88 × 100% ≈ 41%

7 0
3 years ago
I need to know what this answer is
lawyer [7]
3.4x3=10.2...
hope this helps!!
5 0
3 years ago
Y=1/2x-1
Alinara [238K]

Answer:

<h2>Y=1/2x-1</h2>

Find where the expression

1/2x−1 is undefined.

x=1/2

Consider the rational function

R(x)=ax^n/bx^m where n is the degree of the numerator and m is the degree of the denominator.

1. If n<m, then the x-axis, y=0, is the horizontal asymptote.

2. If n=m, then the horizontal asymptote is the line y = ab.

3. If n>m, then there is no horizontal asymptote (there is an oblique asymptote).

Find n and m.n=0m=1

Since n<m, the x-axis, y=0, is the horizontal asymptote.y=0

There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.

No Oblique Asymptotes

This is the set of all asymptotes.

Vertical Asymptotes:

x=1/2

Horizontal Asymptotes:

y=0

No Oblique Asymptotes

<h2>2x+y=4</h2>

Subtract 2x from both sides of the equation.

y=4−2x

Rewrite in slope-intercept form.

The slope-intercept form is

y=mx+b, where m is the slope and b is the y-intercept.

y=mx+b

Reorder 4 and −2x.

y=−2x+4

Use the slope-intercept form to find the slope and y-intercept.

Find the values of m and b using the form

y=mx+b.

m= - 2b=4

The slope of the line is the value of m, and the y-intercept is the value of b.

Slope: −2

y-intercept: (0,4)

Any line can be graphed using two points. Select two x values, and plug them into the equation to find the corresponding y

values.

Find the x-intercept.

x-intercept(s):

(2,0)

Find the y-intercept.

y-intercept(s):

(0,4)

Create a table of the x and y values.

x y

0 4

2 0

Graph the line using the slope and the y-intercept, or the points.

Slope: −2

y-intercept:

(0,4)

Step-by-step explanation:

Hope it is helpful...

8 0
3 years ago
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