Please I need help with these 3 questions with explanation. See attached below.
1 answer:
Answer:
18. compound interest
19. simple interest
20. simple interest
Step-by-step explanation:
For these problems, the initial balance is irrelevant. All that matters is the multiplier of that balance. For simple interest at rate r for t years, the multiplier is ...
simple interest multiplier = (1 +rt)
For interest compounded annually, the multiplier of the initial balance is ...
compound interest multiplier = (1 +r)^t
A spreadsheet can do the computations for you.
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As an example of the computations involved, consider problem 19:
simple interest multiplier = 1 + 0.13·6 = 1.78
compound interest multiplier = 1.10^6 = 1.771561
The latter is less than the former, so the simple interest account will have the (slightly) greater balance at the end of 6 years.
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I found the correct image that accompanies this problem and edited it with my answers.. Pls. see attachment.
Based on the attachment, the correct statements are:
<span>1) DO,2 (x,y) = (2x, 2y)
2) Side Q'S' lies on a line with a slope of -1.
Q'(-6,6) S'(-2,2)
m = y1 - y2 / x1 - x2
m = 6 - 2 / -6 - (-2)
m = 4 / -4
m = -1
</span><span>5) The distance from Q' to the origin is twice the distance from Q to the origin.
</span>
Based on the attachment, the correct statements are:
<span>1) DO,2 (x,y) = (2x, 2y)
2) Side Q'S' lies on a line with a slope of -1.
Q'(-6,6) S'(-2,2)
m = y1 - y2 / x1 - x2
m = 6 - 2 / -6 - (-2)
m = 4 / -4
m = -1
</span><span>5) The distance from Q' to the origin is twice the distance from Q to the origin.
</span>