Answer:
1. 
2. ![x=\pm7i[tex]3.[tex]\pm 12x =a](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fp%3E%3Cp%3E3.%5Btex%5D%5Cpm%2012x%20%3Da)
4. 22
Step-by-step explanation:
1. 



2. 


![x=\pm7i[tex]3. Area of square = [tex]a^{2}](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E3.%20Area%20of%20square%20%3D%20%5Btex%5Da%5E%7B2%7D)
Where a is the side
We are given an area o square = 
So, 


4. We are given that the solution of quadratic equation -9 and 9
So, equation becomes:


So, in the given equation 
z should be the number from which if we subtract 103 so we get 81
Substitute z = 22



Thus the value of z is 22
So first of all we can't start by changing them both into improper fractions
So it would be:
5/2 divided by 13/8
From there you would do 5/2 * 8/13 which could convert to
5/1 * 4/13 which would be 20/13
Use the website Symbolab. It's helped with all of my calculus problems.
Answer:
what are the coordinates
Step-by-step explanation:
Solution,
We have,
Width of rectangle, b = (2.5u+9.8) cm
Length of rectangle, l = (1.5u+3.9) cm
We need to find the expression for the perimeter of the rectangle. The formula for the perimeter of a rectangle is given by:
Perimeter = 2(l+b)
P = 2[(2.5u+9.8)+(1.5u+3.9)]
Collecting like terms
P = 2[(2.5u+1.5u)+(9.8+3.9)]
P=2(4u+13.7)
⇒ P = 8u+27.4
So, the expression for the perimeter of the rectangle is (8u+27.4) cm.