<span>What is the equation of the axis of symmetry of the graph of y + 3x – 6 = –3(x – 2)2 + 4?
</span>A. x=3/2
2000 / 4 = 500
500 + 5% = 25
1500 + 1%= 15
Total cash back = 40$
The first thing to take into account is that the probability of getting any of the six numbers of the dice after rolling it is the same and that probability is 1/6. Here we are being asked about the probability of getting a 1 or a 4 or a 5. In order to find it we need to define which are our favourable cases. Favourable cases are the results we want to get when we roll the dice so getting a 1, a 4 or a 5 are all favourable cases. All the other possible outcomes are unfovourable cases: getting a 2, a 3 or a 6. So we have 3 favourable and 3 unfavourable cases. Adding them we know that the total amount of cases is 6. The probability we are looking for (i'm going to call it P) is given by these quantities I defined:

So the probability written as a simplified fraction is 1/2.
You could model a strait road by using a segment addition postulate. For instance, if you are between point A and B you could calculate how much future you need to go by subtracting the length of the road by the distance you have traveled. Also, segment addition postulate can be used with City Water Lines or Sewer Lines. They can be used to calculate how much pipe is damaged and needs to be replaced.
The number of buckets is directly proportional to the area and the thickness of the wall and inversely proportional to the amount of paint. Mathematically, we can write:
n = k · (a · t) / p
where k is the proportionality constant which we do not know.
We can calculate k with the given data: 5 2-gallon buckets, area of 100 square feet and thickness 3 inches:
k = (n · p) / (<span>a · t)
= (5 </span>· 2) / (100 · 3) = 0.0333
Now that we know the constant, we can calculate the area that can be painted with 8 2-gallon buckets if the thickness is 6 inches:
a = (n · p) / (k<span> · t)
= (8 </span>· 2) / (0.0333 · 6)
= 80 ft²
Please, note that we made sure to have the exact same units of measurements than the previous case.
Therefore, the correct answer is an area of 80 ft².