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2 years ago

Brainiest if correct

Mathematics

2 answers:

Mrac [35]2 years ago

3 0

X=14
3 times 14 is 42-13 is 29

marishachu [46]2 years ago

3 0

X=14 that’s the answer I’m not sure tho

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Svetlana's hair is 4 cm long her hair grows 1.5 sm per month svetlana wants her hair to grow so that it is at least 7 cm long Wr

Radda [10]

Y=4+1.5x

7=4+1.5x

3=1.5x

2=x
It will take at least two months for her hair to be 7 cm

5 0

3 years ago

What is the gcf of 42 and 84

-BARSIC- [3]

Greatest Common Factor of 42 and 84. Greatest common factor (GCF) of 42 and 84 is 42.

7 0

3 years ago

Read 2 more answers

Pleassseeee hhheellppp

hichkok12 [17]

Answer:

a). Point A

b). 90°

c). Anticlockwise

Step-by-step explanation:

As it's clear from the picture attached,

Triangle XYZ has been rotated about a point A to form an image X'Y'Z'.

Angle of rotation is 90° about a point A.

a). Point which is the center of the rotation → point A.

b). Angle of rotation → 90°

c). Direction of rotation → Anticlockwise

6 0

3 years ago

HELP ON A TIMER <br><br> WHAT IS THE x-intercept of the graph?

katen-ka-za [31]

It is 6 just look at the x

8 0

2 years ago

he radioactive element carbon-14 has a half-life of 5750 years. A scientist determined that the bones from a mastodon had lost

elena-s [515]

Answer:

The bones were 12,485 years old at the time they were discovered.

Step-by-step explanation:

Amount of the element:

The amount of the element after t years is given by the following equation, considering the decay rate proportional to the amount present:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The radioactive element carbon-14 has a half-life of 5750 years.

This means that $A(5750) = 0.5A(0)$ , and we use this to find k. So

$A(t) = A(0)e^{-kt}$

$0.5A(0) = A(0)e^{-5750k}$

$e^{-5750k} = 0.5$

$\ln{e^{-5750k}} = \ln{0.5}$

$-5750k = \ln{0.5}$

$k = -\frac{\ln{0.5}}{5750}$

$k = 0.00012054733$

$A(t) = A(0)e^{-0.00012054733t}$

A scientist determined that the bones from a mastodon had lost 77.8 % of their carbon-14. How old were the bones at the time they were discovered?

Had 100 - 77.8 = 22.2% remaining, so this is t for which:

$A(t) = 0.222A(0)$

Then

$0.222A(0) = A(0)e^{-0.00012054733t}$

$e^{-0.00012054733t} = 0.222$

$\ln{e^{-0.00012054733t}} = \ln{0.222}$

$-0.00012054733t = \ln{0.222}$

$t = -\frac{\ln{0.222}}{0.00012054733}$

$t = 12485$

The bones were 12,485 years old at the time they were discovered.

8 0

2 years ago