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e-lub [12.9K]
3 years ago
5

Order from least to greatest

Mathematics
2 answers:
lana66690 [7]3 years ago
8 0
2.603 -> 2.63 -> 2.6312 -> 2.9
insens350 [35]3 years ago
6 0

Here is the correct order:

2.603, 2.63, 2.6312, 2.9

This order shows from least to greatest


Hope this helps you

Brainliest would be appreciated!

-AaronWiseIsBae

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On a hiking trip LaShana notes that she hiked about 12 kilometers every 4 hours. If she continues at this rate’ how many kilomet
Marizza181 [45]

Answer:

First find out how many kilometers per hour

12 kilometers divided by 4 hours = 3 kilometers per hour

3 kilometers times 6 hours = 18 kilometers

Step-by-step explanation:

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clint is covering the sides and top of a box that is .75 feet wide, 13 inches long and 2 inches high with material. how many squ
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4 years ago
8. Suppose you want to buy one pair of pants and several pairs of socks. The pants cost $24.95, and the socks are $5.95 per pair
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8 0
3 years ago
Which equation below illustrates the distributive property? A. 4 x + 5 = 5 + 4 x B. 5 ( x − 3 ) = 5 x − 15 C. 3 ( x + 2 ) + 3 (
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7 0
3 years ago
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best po
mina [271]

Answer:

(a) The point estimate for the population proportion <em>p</em> is 0.34.

(b) The margin of error for the 99% confidence interval of population proportion <em>p</em> is 0.055.

(c) The 99% confidence interval of population proportion <em>p</em> is (0.285, 0.395).

Step-by-step explanation:

A point estimate of a parameter (population) is a distinct value used for the estimation the parameter (population). For instance, the sample mean \bar x is a point estimate of the population mean <em>μ</em>.

Similarly, the the point estimate of the population proportion of a characteristic, <em>p</em> is the sample proportion \hat p.

The (1 - <em>α</em>)% confidence interval for the population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error for this interval is:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The information provided is:

\hat p=0.34\\n=500\\(1-\alpha)\%=99\%

(a)

Compute the point estimate for the population proportion <em>p</em> as follows:

Point estimate of <em>p</em> = \hat p = 0.34

Thus, the point estimate for the population proportion <em>p</em> is 0.34.

(b)

The critical value of <em>z</em> for 99% confidence level is:

z={\alpha/2}=z_{0.01/2}=z_{0.005}=2.58

*Use a <em>z</em>-table for the value.

Compute the margin of error for the 99% confidence interval of population proportion <em>p</em> as follows:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

          =2.58\sqrt{\frac{0.34(1-0.34)}{500}}

          =2.58\times 0.0212\\=0.055

Thus, the margin of error for the 99% confidence interval of population proportion <em>p</em> is 0.055.

(c)

Compute the 99% confidence interval of population proportion <em>p</em> as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

CI=\hat p\pm MOE

     =0.34\pm 0.055\\=(0.285, 0.395)

Thus, the 99% confidence interval of population proportion <em>p</em> is (0.285, 0.395).

6 0
4 years ago
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