Answer:
Just use long subtraction by expanding the decimal places of the whole number. This is done by adding a point, and enough zeros to it to match the number of decimal digits in the other number (digits after the decimal point).
12345678
i.e: 5 - 2.48374827, 2.48374827 has 8 decimal digits, so add 8 zeros after the point.
=
1 1 1 1 1 1 1
5.00000000
-
2.48374827
_______________
2.51625173
7 + 3 = <u>1</u>0, 7 + 2 + <u>1</u> = <u>1</u>0, 8 + 1 + <u>1</u>= <u>1</u>0, 5 + 4 + <u>1</u> = <u>1</u>0, 2 + 7 + <u>1</u> = <u>1</u>0, 3 + 6 + <u>1</u> = <u>1</u>0, 1 + 8 + <u>1</u> = <u>1</u>0, 5 + 4 + <u>1</u> = <u>1</u>0, 2 + 2 + <u>1</u> = <u>5</u><u> </u><u>:</u><u> </u>5.00000000
This is basically borrowing a group of 10s which are the same as 1s in the next decimal place up.
For each digit except the first to the right, let 10 subtract that number from it and minus 1 since the 1 is carried over.
Answer:
The answer is actually 74 days. I know how to algebraically solve this, however I am unsure how to transpose my work onto the computer.
Step-by-step explanation:
I can also tell you that edgenuity will say 74 is correct.
Answer:
9.8596
Step-by-step explanation:
Hello :
<span>sin 2x = sin x and 0 ≤ x ≤ 2π. .....51°
note : sina = sinb equivaut : (a = b +2k</span>π) or ( a = π - b +2kπ) .... k∈ Z
(1) equiv : ( 2x = x +2kπ) or (2x = π - x +2kπ)
( x = 2kπ) or ( x = π/3 + 2kπ/3)....(general solution )
but : 0 ≤ x ≤ 2π
k = 0 : x = 0 , x = π/3
k= 1 : x = 2π , x = π
k = 2 ; x = 5π/3
