You can solve this question by setting up an equation. Dan has twice as many stickers as Cam does. We can call Dan 2x, and Cam x. So the equation would be:
2x-15=x+22.
Then solve this equation:
Add 15 on both sides
2x=x+37
Subtract x on both sides
2x-x=37
X=37.
Therefore Cam has 37 stickers, and Dan has 74 stickers.
Answer:
D
Step-by-step explanation:
I had a test and this is the answer. :)
Answer:
Largest possible mural that can be painted on the wall is 24 feet wide and 13.5 feet high.
Step-by-step explanation:
Design of a mural is 16 in. wide and 9 in. high.
Dimensions of the wall are 24 ft by 14 ft.
If we enlarge the size of the design along the width the wall, scale factor to be used,
Scale factor = ![\frac{\text{Width of the wall}}{\text{Width of the design}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BWidth%20of%20the%20wall%7D%7D%7B%5Ctext%7BWidth%20of%20the%20design%7D%7D)
= ![\frac{24}{16}](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B16%7D)
= ![\frac{3}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D)
With the same scale factor, height of the design will be,
![\frac{3}{2}=\frac{\text{Height of the wall used}}{\text{Height of the design}}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%3D%5Cfrac%7B%5Ctext%7BHeight%20of%20the%20wall%20used%7D%7D%7B%5Ctext%7BHeight%20of%20the%20design%7D%7D)
![\frac{3}{2}=\frac{\text{Height of the wall used}}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%3D%5Cfrac%7B%5Ctext%7BHeight%20of%20the%20wall%20used%7D%7D%7B9%7D)
Width of the wall used = ![\frac{3\times 9}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%5Ctimes%209%7D%7B2%7D)
= 13.5 ft
Therefore, largest possible mural that can be painted on the wall is 24 feet wide and 13.5 feet high.
Answer:
no
Step-by-step explanation:
8÷ 1/2
Copy dot flip
8 * 2/1 = 16
Divide 8 things in half you get 16
1/2 of 8 = 1/2 * 8 = 4
Half of 8 things is 4
They are not the same