Answer:
The first set is a solution, the second is not.
Step-by-step explanation:
Testing by filling in the numbers into the equation:
(1, 1.5): x=1, y=1.5
⇒ 1.5 =? 
· 1 + 
⇒ 1.5 =? +
⇒ 1.5 =? 
⇒ 1.5 =? 1.5 ⇒ Correct: is indeed solution to the equation
(12, 4): x=12, y=4
⇒ 4 =? · 12 +
⇒ 4 =? 
+
⇒ 4 =? 
⇒ Incorrect: this is not a solution for the equation
Answer:
less mass
Step-by-step explanation:
The product has less mass because some of its mass got burned. Hope this helps!
Answer:
Review the proof. A 2-column table with 8 rows. Column 1 is labeled step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine squared (StartFraction x Over 2 EndFraction) = StartFraction sine (x) + tangent (x) Over 2 tangent (x) EndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction sine (X) + StartFraction sine (x) Over cosine (x) EndFraction OverOver 2 (StartFraction sine (x) Over cosine (x) EndFraction) EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction question mark Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction (sine (x)) (cosine (x) + 1) Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = (StartFraction (sine (x) ) (cosine (x) + 1 Over cosine (x) EndFraction) (StartFraction cosine (x) Over 2 sine (x) EndFraction), cosine squared (StartFraction x Over 2 EndFraction) = StartFraction cosine (x) + 1 Over 2 EndFraction, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction cosine (x) + 1 Over 2 EndFraction EndRoot, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 + cosine (x) Over 2 EndFraction EndRoot.
Step-by-step explanation:
Review the proof. A 2-column table with 8 rows. Column 1 is labeled step with entries 1, 2, 3, 4, 5, 6, 7, 8. Column 2 is labeled Statement with entries cosine squared (StartFraction x Over 2 EndFraction) = StartFraction sine (x) + tangent (x) Over 2 tangent (x) EndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction sine (X) + StartFraction sine (x) Over cosine (x) EndFraction OverOver 2 (StartFraction sine (x) Over cosine (x) EndFraction) EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction question mark Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = StartStartFraction StartFraction (sine (x)) (cosine (x) + 1) Over cosine (x) EndFraction OverOver StartFraction 2 sine (x) Over cosine (x) EndFraction EndEndFraction, cosine squared (StartFraction x Over 2 EndFraction) = (StartFraction (sine (x) ) (cosine (x) + 1 Over cosine (x) EndFraction) (StartFraction cosine (x) Over 2 sine (x) EndFraction), cosine squared (StartFraction x Over 2 EndFraction) = StartFraction cosine (x) + 1 Over 2 EndFraction, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction cosine (x) + 1 Over 2 EndFraction EndRoot, cosine (StartFraction x Over 2 EndFraction) = plus-or-minus StartRoot StartFraction 1 + cosine (x) Over 2 EndFraction EndRoot.
Answer:
it is 5 and 7
Step-by-step explanation:
i just took the test
Answer: y= 0.5x + 5.5
Step-by-step explanation: Y = mx + C
SLOPE INTERCEPT FORM:
First we need to find the slope of the two points. Which is y2-y1 / x2-x1.
8 is Y2 and 2 is Y1. 5 is Y2 and -7 is Y1. Plug those numbers into a calculator and solve. The slope (m) is 1/2 or 0.5
Then we have to find C as the slope intercept form is Y = mx + C. To find C we replace x and y with one of the points, and solve as an algebric equation. C will be 5.5
