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DedPeter [7]
3 years ago
12

Are the ways data represented and transmitted with computer law of nature or by law of man?

Computers and Technology
1 answer:
hammer [34]3 years ago
5 0
Data representation is law of man.
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Answer:

oop- welp. that's pretty cool

Explanation:

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Which css property configures the capitalization of text?
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Text-transform

The value can be: uppercase, lowercase or capitalize
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susan wrote the recursive formula for the sequence represented by the exploit formula An=3+2n. put an C net to any correct state
omeli [17]

The recursive formula of the explicit formula A_n = 3 + 2n is A_n = A_{n-1} + 2

The explicit formula is given as:

A_n = 3 + 2n

When n = 1, we have:

A_1 = 3 + 2(1)

A_1 = 5

When n = 2, we have:

A_2 = 3 + 2(2)

A_2 = 7

When n = 3, we have:

A_3 = 3 + 2(3)

A_3 = 9

So, we have:

A_1 = 5

A_2 = 7

A_3 = 9

Rewrite the functions as follows:

A_1 = 5

A_2 = 5 + 2

A_3 = 7 + 2

So, we have:

A_1 = 5

A_2 = A_1 + 2

A_3 = A_2 + 2

Express 2 as 3 - 1

A_3 = A_{3-1} + 2\\

Substitute n for 3

A_n = A_{n-1} + 2

Hence, the recursive formula is A_n = A_{n-1} + 2

Read more about recursive and explicit formulas at:

brainly.com/question/11235928

7 0
3 years ago
Write a program that prompts the user to enter an equation in the form of 10 5, or 10-5, or 1*5, or 13/4, or 13%4. The program s
grandymaker [24]

Answer:

  1. equation = input("Enter an equation: ")
  2. if("+" in equation):
  3.    operands = equation.split("+")
  4.    result = int(operands [0]) + int(operands[1])
  5.    print(operands[0] + "+" + operands[1] + "=" + str(result))
  6. elif("-" in equation):
  7.    operands = equation.split("-")
  8.    result= int(operands [0]) - int(operands[1])
  9.    print(operands[0] + "-" + operands[1] + "=" + str(result))  
  10. elif("*" in equation):
  11.    operands = equation.split("*")
  12.    result = int(operands [0]) * int(operands[1])
  13.    print(operands[0] + "*" + operands[1] + "=" + str(result))  
  14. elif("/" in equation):
  15.    operands = equation.split("/")
  16.    result = int(operands [0]) / int(operands[1])
  17.    print(operands[0] + "/" + operands[1] + "=" + str(result))  
  18. elif("%" in equation):
  19.    operands = equation.split("%")
  20.    result = int(operands [0]) % int(operands[1])
  21.    print(operands[0] + "%" + operands[1] + "=" + str(result))

Explanation:

The solution code is written in Python 3.

Firstly prompt user to enter an equation using input function (Line 1).

Create if-else if statements to check if operator "+", "-", "*", "/" and "%" exist in the input equation. If "+" is found (Line 3), use split method to get the individual operands from the equation by using "+" as separator (Line 5). Output the equation as required by the question using string concatenation method (Line 6).  The similar process is repeated for the rest of else if blocks (Line 7 - 22).  

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Ncomputing and thin client<br>what it is <br>why is done , how it works and how it's <br> done ​
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The term NComputing  is known to be a form of desktop virtualization company that is said to creates hardware and software to form virtual desktops.

The term Thin clients is known to be virtual desktops. They help a lot of users at the same time to share a single operating system instance.

<h3>What is the aim of a thin client?</h3>

In Ncomputer networking, a thin client is known to be a kind of low-performance computer that is known to be optimized and used for setting up a remote connection.

It is often used with a server-based computing system. The server here is one that often does most of the work, such as launching software programs, etc.

Learn more about Ncomputing from

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