The privacy-related risk that threatens Joel is the data breach. The data breach occurs when someone or an individual is likely to breach private information in which the individual is likely to stole, transmit, or gain access to someone else's data without their knowledge or knowing that someone is accessing their personal data.

6 0

2 years ago

0.005098 megaliters to liters. record your answer in whole liters

Dmitriy789 [7]

Your answer would be 5098 liters.

Reason being, because there are 1,000,000 liters in one megalitre, so you just multiply 0.005098 by 1,000,000 to get your answer of 5098 liters.

6 0

2 years ago

A network needs to be set up with 60 subnets. Given the IPv4 class C address 192.168.100.0, what subnet mask value should be use

d1i1m1o1n [39]

We are asked for the subnet mask and the total usable host. There are given values such as a network needs to be set up with 60 subnets given that the IPv4 class C address 192.168.100.0. The subnet mask is "255.255.255.0". The total host is "254".

6 0

3 years ago

In a batch operating system, three jobs are submitted for execution. Each job involves an I/O activity, CPU time and another I/O

Ilia_Sergeevich [38]

Answer:

a) CPU utilization for uniprogramming system = 18.2%

b) CPU utilization for multiprogramming system = 41.379%

Explanation:

IO time = total time – CPU time

For JOB 1

CPU time = 3ms ,

total time= 23ms

IO time = 23-3 = 20ms ,

For JOB 2

CPU time =5ms

total = 29ms

IO time = 29-5 = 24ms

For JOB 3

CPU time = 4ms

total = 14ms

IO time = 14-10 =10ms

1.) In uniprogramming system, operations are performed sequentially

CPU utilization=total CPU time / total real time

CPU utilization =(3+5+4) / (23+29+14)

CPU utilization =0.182 or 18.2%

2) In multiprogramming system, jobs wait for the CPU to get free while performing IO operations concurrently

steps followed by the os

1. IO for 1st job at 0ms

2. IO for 2nd job at 0ms

3. IO for 3rd job at 0ms

4. CPU time for 3rd job at 5ms

5. Next IO job for 3rd job at 9ms END at 14ms

6. CPU time for 1st job at 9ms

7. Next IO job for 1st job at 14ms END at 23ms

8. CPU time for 2nd job at 14ms

9. Next IO job for 2nd job at 15ms END at 29ms

CPU time is 3+5+4 =12ms

Total execution time = 29ms

CPU utilization = 12*100/29= 41.379%

5 0

2 years ago