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vazorg [7]
3 years ago
14

Suppose that to make the golf team you need to score no more than 74 on average over 5 games. If you scored 77, 71, 77, and 67 i

n your first 4 games what is the highest score you can shoot in you 5th game and still make the team
Mathematics
2 answers:
lord [1]3 years ago
6 0
A score of 78

77+71+77+67+78=370
370/5=8
Stels [109]3 years ago
3 0

Answer:

78 is the correct answer.

Step-by-step explanation:

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The equation y=ax describes the graph of a line. if the value is negative the line is what?
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If the value of a is negative the line is decreasing.

Step-by-step explanation:

The value of a, the coefficient of x, is the slope.

If the slope is positive, the line is increasing from left to right.

If the slope is negative, the line is decreasing from left to right.

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What is the volume of the cone?
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16pi cm^3

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3 years ago
10 decreased by twice a
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3 years ago
Use the graph of △ABC with midsegments DE, EF and DF. Show that EF is parallel to AC and that EF=1/2 AC
Vinvika [58]

According to the midsegment theorem, the midsegments are parallel to

and half the length of the opposite side.

The completed statement are as follows;

  • Because the slopes of \overline{EF} and \overline{AC} are both<u> -4</u>, \overline{EF} ║ \overline{AC}
  • EF = \underline{\sqrt{17}} and AC = \underline{2 \cdot \sqrt{17} }
  • Because \underline{\sqrt{17} } = \underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17} }, EF = \frac{1}{2} \cdot AC

<u />

Reasons:

From the given graph of ΔABC, we have;

Coordinates of the points <em>A</em>, <em>B</em>, and <em>C </em>are; A(-5, 2), B(1, -2), and C(-3, -6)

The coordinates of the point D and E on \mathbf{\overline{DE}} are; D(-4, -2), and E(-2, 0)

The coordinates of the point F is; F(-1, -4)

  • Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

\displaystyle Slope \ of \ line \ \overline{AC} = \mathbf{\frac{(-6) - 2}{-3 - (-5)}  = \frac{-8}{2}} = -4

\displaystyle Slope \ of \ line \ \overline{EF} = \frac{0 - (-4)}{-2 - (-1)}  = \frac{4}{-1} = -4

  • Length \ of \ segment,\ l = \sqrt{\left (x_{2}-x_{1}  \right )^{2}+\left (y_{2}-y_{1}  \right )^{2}}

Length of EF  = √((-1 - (-2))² + (-4 - 0)²) = √(17)

Length of AC = √((-3 - (-5))² + (-6 - 2)²) = √(4 × 17) = 2·√(17)

Therefore, we have;

Because the slope of \mathbf{\overline {EF}} and \mathbf{\overline {AC}} are both , <u>-4</u>, \overline {EF} ║ \overline {AC}. EF = \underline{\sqrt{17}}, and AC

= \underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}},. Because \underline{\sqrt{17}} = \underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}, EF =\mathbf{ \frac{1}{2} AC}

Learn more about midsegment theorem of a triangle here:

brainly.com/question/7423948

8 0
3 years ago
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