Dont give me files. answer on here only.

Mathematics

2 answers:

vivado [14]3 years ago

5 0

You plug in the numbers. For example, for the first one you plug in 7 to 4.9=0.7m.
You replace the m with 7 then solve. 4.9=0.7(7)
4.9=4.9
which will make the answer infinite solutions since it is a true statement.

zvonat [6]3 years ago

3 0

Answer:

Look at the image.

Step-by-step explanation:

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Which of the following is the quotient of b and a?

vlabodo [156]

$\bf 19^{\frac{7}{4}}\cdot \sqrt[a]{19^b}=19^{\frac{5}{2}}\sqrt{19}\\\\
-----------------------------\\\\
a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-----------------------------\\\\
thus\qquad 19^{\frac{7}{4}}\cdot 19^{\frac{b}{a}}=19^{\frac{5}{2}}\cdot 19^{\frac{1}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{5}{2}+\frac{1}{2}}
\\\\\\
$

$\bf 19^{\frac{7}{4}+\frac{b}{a}}=19^{\frac{6}{2}}\implies 19^{\frac{7}{4}+\frac{b}{a}}=19^3\impliedby 
\begin{array}{llll}
\textit{same base, thus}\\
\textit{exponents must be the same}
\end{array}
\\\\\\
\cfrac{7}{4}+\cfrac{b}{a}=3\implies \cfrac{b}{a}=3-\cfrac{7}{4}$

5 0

3 years ago

Lie is solving the quadratic equation by completing the square.

wel

we have

$3x^{2} + 18x - 8 = 0$