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3 years ago

5.14x+1.76+0.9x−x=32

Mathematics

1 answer:

Novay_Z [31]3 years ago

7 0

Answer:

x=6

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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What is the coefficient of q in the sum of (2/3q-3/4) and(-1/6q-r)?

Harlamova29_29 [7]

Answer:

The coefficient is $\frac{1}{2}$

Step-by-step explanation:

The given sum is

$(\frac{2}{3}q -\frac{3}{4})+(-\frac{1}{6}q-r)$

We can choose to add only the coeffients of $q$ or simplify the whole sum.

$=\frac{2}{3}q -\frac{1}{6}q-\frac{3}{4})-r)$

We collect the LCM for the $q$ terms;

$=\frac{4-1}{6}q-\frac{3}{4})-r)$

This will give us;

$=\frac{3}{6}q-\frac{3}{4})-r)$

Which is the same as

$=\frac{1}{2}q-r-\frac{3}{4}$

The coefficient is $\frac{1}{2}$

6 0

3 years ago

Read 2 more answers

Which of the following representations are functions?

allsm [11]

Answer: A and B only

Step-by-step explanation:

In function, for one value of x there must be only one value of y.

4 0

3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago

What is larger 27 feet 7 yards or 312 inches

olga2289 [7]

312 inches in feet: 26

7 yards in feet: 21 ft

6 0

4 years ago

Read 2 more answers

Help please pre calculus

Jobisdone [24]

Since a log graph is with base 10 and a ln graph is with base e (2.something), the log x graph will clearly have smaller numbers (as, for example, log100=2 and ln100=around 4.6). In addition, you only have to multiply a number by e to increase the power by 1 but you have to multiply a number by 10 (which is significantly larger than e) to increase logx's power by 1, therefore proving that the log x graph will grow slower

6 0

3 years ago