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Ghella [55]
3 years ago
6

0.9(3÷2.25− 1/8 (1 2/3 1/9 ))− 4/7 ÷0.8. i would like to know what this equals if you could help that would be great.

Mathematics
1 answer:
mario62 [17]3 years ago
7 0

Answer:

781/1680

Step-by-step explanation:

Don't you have a calculator?

I assume that by (1 2/3 1/9), you mean (1+2/3)*(1/9)

Assuming that you put all necessary parentheses:

781/1680, approx. 0.4648809523809524



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What is an equation of the line that passes through the points (-2, 1) and (-8, 4)?
Grace [21]

Answer:

<h2>3x + 6y = 0</h2>

Step-by-step explanation:

Equation of a line = y = mx + c

where m = slope

m = (1 - 4) / (-2 - (-8))

<h3>m = -3 / 6</h3>

y - 1 = -3/6 (x + 2)

6y - 6 = -3x - 6

3x + 6y = 0

4 0
3 years ago
Evaluate 3m2 -4 if m = -3​
zhenek [66]

Answer:

23

Step-by-step explanation:

3m^{2} - 4 = 3 * (-3)^{2} - 4 = 3 * 9 - 4 = 27 - 4 = 23

8 0
3 years ago
Quick question if I had a problem that was sin x = 18.9/20 =.945 how would I inverse sin of both sides ?
galben [10]

Answer:

The result is about 70.9 degrees

Step-by-step explanation:

Easy for a calculator.  If you're not using a calculator, it's much more tedious!

There is an inverse sine key on your calculator, but you may have to press a key (likely labeled 2nd or INV) first.  The attached image shows a TI-83 display.  To get the inverse sine, I first pressed the yellow 2nd key, then the sin key.

Check MODE first to make sure you're measuring angles in degrees (if that's what you want!).  Some calculators display angle mode with a small letter at the top of the display, D, R, or G usually.

The left side of the equation produces just x.

\sin{x}=.945\\\\\sin^{-1}(\sin{x})=\sin^{-1}(.945)\\x=\sin^{-1}(.945) \approx 70.9^\circ

6 0
3 years ago
Help me pleasseeeeeee
REY [17]
The answer is B. 70 _____
6 0
3 years ago
Read 2 more answers
These circles are:<br><br> A. tangent<br> B. congruent<br> C. congruent<br> D. none of these
Goshia [24]

Answer:

A. tangent

Step-by-step explanation:

Hi there!

Tangent circles are circles that intersect (or "touch") at exactly one point. These circles appear to have this characteristic.

I hope this helps!

3 0
3 years ago
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