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Contact [7]
3 years ago
5

How do you find the slope intercept form with only one given point?

Mathematics
1 answer:
noname [10]3 years ago
3 0
Straight-line equations, or "linear" equations, graph as straight lines, and have simple variable expressions with no exponents on them. If you see an equation with only x and y — as opposed to, say x2 or sqrt(y) — then you're dealing with a straight-line equation.
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A sales associate in a department store earns a commission on each suit and each pair of shoes sold. One week, she earned $47 in
ahrayia [7]
For this one you have to make the equations. And what I like to do is write it out, like this.One Week- $473 suits 1 shoes (pairs)
Another Week- $1077 suits 2 shoes (pairs)
Then I make/choose my variables.For suits, it's going to be x.And For shoes let's do y.(Or if you would like better you can do x and y, which ever works best for you)
Now for the equations:One Week,   47= 3x +1yAnother Week,   107= 7x + 2y
Now it's time for the Substitution! Your last problem had it easier because it was already in the form, y=mx+b, but since ours aren't we have to change it to y=mx+b.
One Week,  -0.33y + 15.67 =x Another Week,  -0.29y + 15.29 =x
Now you can use substitution. :)For y i got 9.5 or 9.50.For x, i got 12.34
So the answer is (9.5,12.34) or (12.34, 9.5)
8 0
3 years ago
A seafood restaurant owner orders perch and salmon. Perch is four dollars per pound and salmon is three dollars per pound. He wa
Svetach [21]

Answer:

He can buy at least 34 pounds of fish.

Step-by-step explanation:

4x + 3x \leq 240

7x \leq 240

(240 divided by 7 gives you a decimal, so you would round it to the nearest whole number)

x \leq 34

0 0
3 years ago
Find an equation for the line tangent to the curve y=x^3-4x+8 at the point (4,56)
Alexxandr [17]
<span><span><span>y2</span>(<span>y2</span>−4)=<span>x2</span>(<span>x2</span>−5)</span><span><span>y2</span>(<span>y2</span>−4)=<span>x2</span>(<span>x2</span>−5)</span></span><span> Multiplying the polynomials gets us to </span><span><span><span>y4</span>−4<span>y2</span>=<span>x4</span>−5<span>x2</span></span><span><span>y4</span>−4<span>y2</span>=<span>x4</span>−5<span>x2</span></span></span><span>. Taking the derivative with respect to </span><span>xx</span><span> gets us: </span><span><span>4<span>y3</span><span>y′</span>−>!8y<span>y′</span>=4<span>x3</span>−10x</span><span>4<span>y3</span><span>y′</span>−>!8y<span>y′</span>=4<span>x3</span>−10x</span></span><span>. Factoring to get </span><span><span>y′</span><span>y′</span></span><span> by itself: </span><span><span><span>y′</span>(4<span>y3</span>−8y)=4<span>x3</span>−10)</span><span><span>y′</span>(4<span>y3</span>−8y)=4<span>x3</span>−10)</span></span><span>. Divide through to get </span><span><span>y′</span><span>y′</span></span><span> by itself: </span><span><span><span>y′</span>=<span><span>4<span>x3</span>−10x</span><span>4<span>y3</span>−8y</span></span></span><span><span>y′</span>=<span><span>4<span>x3</span>−10x</span><span>4<span>y3</span>−8y</span></span></span></span><span>. You could make your life a bit easier by factoring this into </span><span><span><span>y′</span>=<span><span>2x(2<span>x2</span>−5)</span><span>4y(<span>y2</span>−2)</span></span></span><span><span>y′</span>=<span><span>2x(2<span>x2</span>−5)</span><span>4y(<span>y2</span>−2)</span></span></span></span><span>. You could cancel out a factor of </span><span>22</span><span> to get </span><span><span><span>y′</span>=<span><span>x(2<span>x2</span>−5)</span><span>2y(<span>y2</span>−2)</span></span></span><span><span>y′</span>=<span><span>x(2<span>x2</span>−5)</span><span>2y(<span>y2</span>−2)</span></span></span></span><span>. To find the slope, plug in your points </span><span><span>x=0,y=−2</span><span>x=0,y=−2</span></span><span> into our equation for </span><span><span>y′</span><span>y′</span></span><span> to find the slope of the line. Note that the slope is </span><span>00</span><span>. To find the </span>equation<span> of the tangent line, use that value for </span><span>mm</span><span> you just found (</span><span><span>m=0</span><span>m=0</span></span><span>) and your given points into the point-slope formula and you find that the tangent line is </span><span><span>y=−2</span><span>y=−2</span></span><span>.

Thats what my Aunt said... Idk</span>
4 0
3 years ago
What is the value of x in the equation 6(x-1)=4x
Schach [20]
6x - 6 = 4x
2x = 6
x = 3
8 0
3 years ago
Read 2 more answers
Directions: Given the point and slope, write the equation of the line.<br> (4, 2); slope = 36
olga nikolaevna [1]

Answer:

y - 2 = 36(x - 4)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 36 and (a, b ) = (4, 2 ) , then

y - 2 = 36(x - 4) ← equation of line

5 0
3 years ago
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