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zalisa [80]
3 years ago
5

Andy estimated that he would need 75 feet of lumber for a tree house project. he later found that the actual amount of lumber ne

eded was 64 feet. what was the percent error of andy's estimation?
Mathematics
1 answer:
Kipish [7]3 years ago
8 0
Step 1
<span>Calculate the error
</span>error=75-64-----> 11 ft

step 2
<span>Divide the error by the exact value
</span>11/64=0.1719

step 3
<span>Convert that to a percentage 
</span>0.1719*100=17.19%

the answer is
17.19%

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Max drives 105 miles per week. If he drives an equal number of miles each day, then how many miles will max drive in a 30 day mo
SIZIF [17.4K]

Answer:

350 miles

Step-by-step explanation:

if max drives 105 miles per week

you should first find out how many miles max drives per day.

there are 7 days in a week so :

105 ÷ 7 = 15

so for 30 days max will drive 15 × 30 = 350 miles

1 day : 15 miles

30 days : 350 miles

8 0
2 years ago
An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,
butalik [34]

Answer:

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

s=\sqrt{r_{A}^{2}+r_{B}^{2}}

Rate of change of such distance can be found by the deriving the expression in terms of time:

\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }

Where \frac{dr_{A}}{dt} = 500\,\frac{mi}{h} and \frac{dr_{B}}{dt} = 550\,\frac{mi}{h}, respectively. Distances of each airliner at 2:30 PM are:

r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi

r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi

The rate of change is:

\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

6 0
3 years ago
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-Dominant- [34]

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3 years ago
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alexgriva [62]
The answer of this problem is x=14
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3 years ago
Which expression represents the prime factorization of 243?
Anika [276]

Answer:

\boxed{3^5}

Step-by-step explanation:

<em>Hey there!</em>

Look at the image below↓

By looking at the image we can tell the PR expression is 3^5.

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4 0
3 years ago
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