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LenaWriter [7]
3 years ago
13

Explain the steps used to solve x - 2 = v(x + 10) and check for extraneous solutions.

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0
---------------------------------------------------
Question
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x - 2 = √<span>(x + 10) 

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Square both sides
</span>---------------------------------------------------
(x - 2)² = (√(x + 10))²
(x - 2)² = (x + 10)   ← square and square root would will net off each other

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Remove brackets
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x² - 4x + 2² = x + 10
x² - 4x + 4 = x + 10

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minus x + 10 on both sides
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x² - 4x + 4 - x - 10 = 0
x² - 5x - 6 = 0

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Factorise the left side
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(x - 6)(x + 1) = 0

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Apply zero product property 
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x -6 = 0  or  x +1 = 0

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Solve x
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x = 6 or x = -1

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Answer: x = 6 or x = -1
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3 years ago
zoe paid $18.60 in sales tax and tips for her dinner. The sales tax rate is 11%, and she tipped 20%. (the sales tax does not app
arsen [322]

Answer:

$13.97  was the price of the dinner b4 tax and tip

Step-by-step explanation:

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5 0
3 years ago
Which statement is true about the domain of y = 3(2^-x)? Explain.
SVEN [57.7K]
We want to determine the domain of {y=3 \cdot 2^{-x}=3 \cdot ({2^{-1}})^x=3 \cdot ({ \frac{1}{2}})^x

any function of the form y=f(x)=a \cdot b^x is called an "exponential function",
the only condition is that b is positive and different from 1, and a is a nonzero real number.

The domain of such functions is all real numbers.

That is for any x, the expression <span>3(2^-x) "makes sense".



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8 0
3 years ago
For which of the following compound inequalities is there no solution? ​
Bess [88]

Answer:

(a)6m \le - 36 and m + 24 > 20

Step-by-step explanation:

Required

Which of a to d has no solution

(a)6m \le - 36 and m + 24 > 20

We have: m + 24 > 20

Sole for m

m >20 - 24

m >-4

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Divide by 6

m \le -6

So, we have:

m \le -6 and m >-4

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m >-4 implies that m = -3,-2,-1,0.....

<em>Hence, there is no solution</em>

8 0
3 years ago
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