The answer is going to be (5+10)/5. Hope that helped
The percentage of students that passed the exam is 25.2%
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<u>The given parameters;</u>
- number of the males, = 85
- number of the females, = 30
- percentage of the female that passed = 40%
- percentage of the male that passed, = 20%
<u>To find:</u>
- the percentage of students that passed the exam
The number of the male students that pass the exam;

The number of the female students that pass the exam;

The total number of students in the school;
= 85 + 30
= 115
The total number of the students that passed the exam;
= 17 + 12
= 29
The percentage of students that passed the exam;

Thus, the percentage of students that passed the exam is 25.2%
Learn more here: brainly.com/question/1163846
Answer:
2
Step-by-step explanation:
Answer:
Step-by-step explanation:
Hello!
You have two populations of interest and want to compare them. If you define the study variables as:
X₁: average hourly wages of an employee of the Downtown store.
n₁= 25
X[bar]₁= $9
S₁= $2
X₂: average hourly wages of an employee of the North Mall store.
n₂= 20
X[bar]₂= $8
S₂= $1
Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:
95% CI for μ₁ - μ₂
(X[bar]₁-X[bar]₂) ± 


Sa= 1.64

(9-8)±2.017*
[0.007636;1.9923]
I hope it helps!