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kodGreya [7K]
4 years ago
14

How many kiloliters r in

Mathematics
2 answers:
34kurt4 years ago
8 0
Remember
KILO
HECTO
DECA
(UNIT)
DECI
CENTI
MILLI

The answer is Liters
Marysya12 [62]4 years ago
7 0
1,09 kl =1,090 l (liters)
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The answer is going to be (5+10)/5. Hope that helped
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3 years ago
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Tion 15/30
vitfil [10]

The percentage of students that passed the exam is 25.2%

<u />

<u>The given parameters;</u>

  • number of the males, = 85
  • number of the females, = 30
  • percentage of the female that passed = 40%
  • percentage of the male that passed, = 20%

<u>To find:</u>

  • the percentage of students that passed the exam

The number of the male students that pass the exam;

= 0.2 \times 85 \\\\= 17

The number of the female students that pass the exam;

= 0.4 \times 30 \\\\= 12

The total number of students in the school;

= 85 + 30

= 115

The total number of the students that passed the exam;

= 17 + 12

= 29

The percentage of students that passed the exam;

= \frac{total \ number \ that \ passed }{total \ number \ of \ the \ students} \times 100\% \\\\= \frac{29}{115} \times 100\%\\\\= 25.2 \%

Thus, the percentage of students that passed the exam is 25.2%

Learn more here: brainly.com/question/1163846

6 0
3 years ago
Tristan bought an orange that weighs 1/5 pound. He cut the orange into 8 slices. How much does each orange slice weigh?
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Step-by-step explanation:

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3 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, two ind
liberstina [14]

Answer:

Step-by-step explanation:

Hello!

You have two populations of interest and want to compare them. If you define the study variables as:

X₁: average hourly wages of an employee of the Downtown store.

n₁= 25

X[bar]₁= $9

S₁= $2

X₂: average hourly wages of an employee of the North Mall store.

n₂= 20

X[bar]₂= $8

S₂= $1

Both samples taken are independent, assuming that both populations are normal and that their population variances are equal I'll use the Student's-t statistic with a pooled sample variance to calculate the Confidence interval:

95% CI for μ₁ - μ₂

(X[bar]₁-X[bar]₂) ± t_{n_1+n_2-2; 1-\alpha /2} * (Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } )

Sa^2= \frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}

Sa^2= \frac{24*4+19*1}{25+20-2}= 2.67

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(9-8)±2.017*(1.64*\sqrt{\frac{1}{25} +\frac{1}{20} } )

[0.007636;1.9923]

I hope it helps!

6 0
3 years ago
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