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baherus [9]
2 years ago
15

Find the arc length, x, when , r= 1 and 8 = 2.5 radians. Х 2.5 1 x = [?]

Mathematics
1 answer:
Anna11 [10]2 years ago
6 0

Answer:

x = 2.5

Step-by-step explanation:

The arc length x is calculated as

x = circumference of circle × fraction of circle

  = 2πr × \frac{2.5}{2\pi } ( cancel 2π on numerator/ denominator )

x = 1 × 2.5 = 2.5

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First: The student rotated the figure 90° clockwise.
Second: The student reflected across the x-axis.

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Nina has some nickels and 9 pennies in her pocket. Her friend, Maurice has twice as many nickels as Nina. Together these coins a
algol13

So Maurice would have 2N nickels  

Total number of coins is N + 2N + 9 = 3N + 9  

Each nickel is 5 pennies  

3N of nickels = 15N pennies  

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Their worth is 84 cents  

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Jasper has an annual salary of $71,000, and his company pays him twice a month. What is the gross income per paycheck that Jaspe
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What is the greatest possible product of a 3-digit number and a 1 digit number
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8,991 which is the product of 999 times 9
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9. Find the area of the figure to the right.<br> area<br> 14 in
zlopas [31]

Answer:

1. 200 in.^2

2.

Step-by-step explanation:

1. Area of a trapezium=1/2(a+b)height

a=14 in.

b=20 in.+6 in. = 26 in.

height= ?

height can be gotten by using

formula : Soh Cah Toa

Toa is tangent∆= opposite/ adjacent

∆ = 60°

opp=? adj=6 in.

Tan 60° =opp/6 in.

Tan 60° = 1.732

1.732= opp/ 6 in.

opp=1.732*6 in.

opp = 10.392 approximately= 10 in.

Area of trapezium= 1/2*(14+26)*10(in.^2)

Area of trapezium= 1/2*40*10

= 1/2*400

= 200 in.^2 .

2. Area of triangle= 1/2* base* height

for first triangle =

base=4m

height =15m

Area: 1/2*4*15 ,1/2*60= 30m^2

second triangle =

base:?

height: 15m

using Pythagorean theorem;

hyp^2 = opposite ^2 + adjacent ^2

17^2 = 15^2 + adj^2

289= 225 + adj^2

adj^2 = 289-225= 64

square root

adj = 8m

area of second triangle : 1/2*8*15

: 1/2*120 :60m^2

total area: 30 m^2 +60m^2

==90 m^2

8 0
3 years ago
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