Solve p^2+6p+8 by using square roots<br> Thank You!

a matinee ticket costs $6 per adult and $1 per child. On a certain day, the total number of adults (a) and children (c) who saw

vovikov84 [41]

Answer:

The number of adults who saw a movie that day is 7

and

the pair of equations that can be solved to find the numbers is

6x+y = 70

x + y = 35

Step-by-step explanation:

Let the total no. of adults who saw the move be x

Let the total no. of child who saw the move be y

Given that the total number of adults (a) and children (c) who saw a movie was 35

thus. x + y = 35

cost of ticket for 1 adult = $6

cost of ticket for 1*x adult = $6*x = $6x

cost of ticket for x adult = $6x

cost of ticket for 1 child = $1

cost of ticket for 1*y child = $1*y = $y

cost of ticket for y child = $y

Total cost for x adult and y child = $(6x+y) _______(2)

Given that he total money collected was $70

Thus, we have two equations

6x+y = 70 -------(1)

x + y = 35

y = 35 - x (using this value of y in equation 1 we have)

6x + 35 - x = 70

=> 5x = 70 -35 = 35

=> x = 35/5 = 7

The number of adults who saw a movie that day is 7

and

the pair of equations that can be solved to find the numbers is

6x+y = 70

x + y = 35

5 0

3 years ago

44% is equivalent to what fraction in reduced terms?

Vera_Pavlovna [14]

Answer:

44/100 will be reduced to 11/25

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I need helppp ... . . . .

oee [108]

I actually believe that the answer is A

3 0

3 years ago

Read 2 more answers

This week, we are covering relationships that can be approximated by linear equations. For instance, y = 453x + 3768 represents

lana [24]

Answer:

See explanation below.

Step-by-step explanation:

We assume that the data is given by :

x: 30, 30, 30, 50, 50, 50, 70,70, 70,90,90,90

y: 38, 43, 29, 32, 26, 33, 19, 27, 23, 14, 19, 21.

Where X represent the cost for scholarships in thousands of dollars and y represent the cost of life for an academic semester (The data comes from the web)

We can find the least-squares line appropriate for this data.

For this case we need to calculate the slope with the following formula:

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

So we can find the sums like this:

$\sum_{i=1}^n x_i = 30+30+30+50+50+50+70+70+70+90+90+90=720$

$\sum_{i=1}^n y_i =38+43+29+32+26+33+19+27+23+14+19+21=324$

$\sum_{i=1}^n x^2_i =30^2+30^2+30^2+50^2+50^2+50^2+70^2+70^2+70^2+90^2+90^2+90^2=49200$

$\sum_{i=1}^n y^2_i =38^2+43^2+29^2+32^2+26^2+33^2+19^2+27^2+23^2+14^2+19^2+21^2=9540$

$\sum_{i=1}^n x_i y_i =30*38+30*43+30*29+50*32+50*26+50*33+70*19+70*27+70*23+90*14+90*19+90*21=17540$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=49200-\frac{720^2}{12}=6000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}=17540-\frac{720*324}{12}{12}=-1900$

And the slope would be:

$m=-\frac{1900}{6000}=-0.317$

Nowe we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{720}{12}=60$

$\bar y= \frac{\sum y_i}{n}=\frac{324}{12}=27$

And we can find the intercept using this:

$b=\bar y -m \bar x=27-(-0.317*60)=46.02$

So the line would be given by:

$y=-0.317 x +46.02$

We have an inverse linear relationship since the slope is negative between the variables of interest.

8 0

4 years ago

−3 1/0−(−2 1/0)

lianna [129]

I believe it's "-1" hope I helped

4 0

3 years ago

Solve p^2+6p+8 by using square roots Thank You!