We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
Answer:
It is a diagnal line that goes through (0,0) and (1,1) and has a slope of 1
Step-by-step explanation:
<em>The</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>X </em><em>is</em><em> </em><em>9</em><em>2</em><em>.</em>
<em>pl</em><em>ease</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>for</em><em> </em><em>full</em><em> </em><em>solution</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>
Answer:
Option A
Step-by-step explanation:
A = 3 +3 +3+3 = 12
B = 3⁴ = 81
C = 3² × 3² = 9 × 9 = 81
D = 3× 3 × 3 × 3 = 81