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Dmitriy789 [7]
3 years ago
7

9x + 3y -2 what is the term(s) varible(s) coefficient(s) and constant(s)​

Mathematics
1 answer:
DanielleElmas [232]3 years ago
7 0

Answer: The coefficients is 9,3,2 and the constants is 9x and 3y. The varible is x,y and the term is 2

Step-by-step explanation:

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Mr. McGee mowed 4/5 of his lawn. His three sons finished the mowing. Each son mowed the same amount. How much of the lawn did ea
liubo4ka [24]

Answer:

1 fifteenth, or 1/15

Step-by-step explanation:

If there are 3 sons multiply the fraction by 3 and then you have 12/15 because 12/15 is equal to 4/5, so the remaining is 3 out of 15, so divide that between the 3 sons and boom, 1/15th per son.  

5 0
3 years ago
In order to answer the question correctly, please use the image below:
Maurinko [17]

Answer:

240

Step-by-step explanation:

m xyz 2(120)

(sorry about the explaination)

5 0
3 years ago
Read 2 more answers
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this question, we have that:

\pi = 0.21

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.21*0.79}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.21*0.79}

\sqrt{n} = \frac{1.645\sqrt{0.21*0.79}}{0.03}

(\sqrt{n})^2 = (\frac{1.645\sqrt{0.21*0.79}}{0.03})^2

n = 498.81

Rounding up

A sample of 499 is needed.

8 0
2 years ago
Help??? Which Choice is correct
marusya05 [52]

Answer:

choice B should be right

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Can someone please help me ASAP!¡
Nataliya [291]
1) No. 28/21 does not end up being equal to 2.
2) No. 45/5 does not equal 18/2
3) No. For something to be proportional, it should at least have the smaller number in the same place.
4) No. 25/12 does not equal 53/40
5) Yes. 4/2 is equal to 14/7
6) Yes. 4/1 is equla to 12/3
7) No. For something to be proportional, it should at least have the smaller number in the same place.
8) No. 44/9 is not equal to 36/11
9) Yes. 10/5 is equal to 16/8
10) Yes. 24/12 is equal to 14/7
11) No. 24/4 is not equal to 42/9
12) Yes. Both equal 1.
13) Yes. 20/5 is equal to 44/11
14) No. 44/40 is not equal to 34/30
15) Yes . 40/4 is equal to 10/1
16) Yes. 36/4 is equal to 45/5
17) No. 16/2 is not equal to 13/1
18) No. 38/9 is not equal to 28/7
19) Yes. This is a common proportion.
20) Yes. 50/25 is equal to 2.
21) Yes. 36/24 is equal to 3/2.
22) Yes. 18/12 is equal to 42/28
23) No. 33/42 is not equal to 27/37
24) No. 34/7 is not 4
25) Yes. The second proportion listed is half of the first
26) Yes. This is proportional.
27) Yes. This is proportional.
28) Yes. This is proportional.
29) No. This is not proportional.
30) No. This is not proportional
31) Yes. This is proportional.
32) Yes. This is proportional
33)
34)
35)
36)
37)
38)
39)
40)
I hope this helped. I left the last few unsolved so you could follow the patterns to find them out!

3 0
3 years ago
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