Answer:
62 2/5
Step-by-step explanation:
62 is just the whole number and then you have 4 tenths, which is 4/10 which can be simplified to 2/5, so it's 62 2/5
You would need 2008 inches of board to make the planter box.
I'm assuming that ? is a minus sign
3x+4y-8=0
a.
perpendicular lines have slopes that multiply to -1
ok
for ax+by-c=0
the slope is -a/b
so
3x+4y-8=0
slope=-3/4
perpendicular lines have slopes that multiply to get -1
-3/4 times what=-1
times both sides by -4/3
what=4/3
the slope is 4/3
y=mx+b
m=slope
b=y intercept
y=4/3x+b
we are given the point (2,3)
x=2 and y=3
3=4/3(2)+b
3=8/3+b
3-8/3=b
9/3-8/3=b
1/3=b
y=4/3x+1/3 is the equation
b. the slope is 4/3
c. the y intercept is 1/3
d. see attachment
The problem statement gives a relation between the amount removed from one bag and the amount removed from the other. It asks for the amount remaining in each bag. Thus, there are several choices for variables in this problem, some choices resulting in more complicated equations than others.
Let's do it this way: let x represent the amount remaining in bag 1. Then the amount removed from bag 1 is (100-x). The amount remaining in bag 2 is 2x, so the amount removed from that bag is (100-2x). The problem statement tells us the relationship between amounts removed:
... (100 -x) = 3(100 -2x)
... 100 -x -3(100 -2x) = 0 . . . . . . subtract the right side
... 5x -200 = 0 . . . . . . . . . . . . . . eliminate parentheses and collect terms
... x -40 = 0 . . . . . . . . . . . . . . . . .divide by 5
... x = 40 . . . . . . . . . . . . . . . . . . . add 40
- 40 kg is left in the first bag
- 80 kg is left in the second bag
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<u>Check</u>
The amount removed from the first bag is 60 kg. The amount removed from the second is 20 kg. The amount removed from the first bag is 3 times the amount removed from the second bag, as described.