All categories

3 years ago

Please help with this question thanks

Mathematics

1 answer:

ololo11 [35]3 years ago

8 0

the highest fair would be 240 customers charging 11 dollars with a profit of 2,640 dollars

You might be interested in

Help me in this one pls I give 15 pts

scoundrel [369]

Answer:

23.7555090109

Step-by-step explanation:

sin= opposite/hypotenuse

sin(53) = BC/60cm

BC= sin(53)*60 = 23.7555090109

6 0

2 years ago

Three numbers are in an arithmetic progression with a common difference of 6. if 4 is subtracted from the first number, 1 is sub

UkoKoshka [18]

Answer:

either of {-9.5, -3.5, 2.5} or {7, 13, 19}

Step-by-step explanation:

Let x represent the first number of the arithmetic sequence. Then the second number is x+6, and the third number is x+12. The geometric sequence is then ...

(x -4), (x +5), 3(x+9)

The common ratio is then ...

(x +5)/(x -4) = 3(x +9)/(x +5)

Cross-multiplying gives ...

(x +5)² = 3(x -4)(x +9)

x² +10x +25 = 3x² +15x -108 . . . . eliminate parentheses

0 = 2x² +5x -133 . . . . . . . . . . . . . . subtract the left side

0 = (2x +19)(x -7) . . . . . . . . . . . . . . factor

x = -9.5 . . or . . 7

The possible original three numbers are ...

{-9.5, -3.5, 2.5} . . or . . {7, 13, 19}

8 0

2 years ago

20 POINTS FOR THE FIRST PERSON TO ANSWER

MAVERICK [17]

Answer: its A

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Is 8 one tenths of 80

Otrada [13]

Yeah 8 is 1/10th of 80.

6 0

3 years ago

Read 2 more answers

Please help!!!! will mark brainlest

fomenos

Answer: B. 84 in²

Step-by-step explanation:

Divide the area into two regions: a rectangle and a trapezoid (depicted in the attached photo).

Find the area of the rectangle:

Area of a rectangle=length*width

Area of rectangle=(5 in)( 10 in)

Area of rectangle=50 in²

Next, calculate the area of the trapezoid:

Area of trapezoid= $\frac{h(b_{1} +b_{2}) }{2}$

h=10 in-6 in

h=4 in

$b_{1} =15 in$

$b_{2} =15 in-5 in$

$b_{2} =10 in$

Area of trapezoid= $\frac{4in(7 in+10in)}{2}$

Area of trapezoid= $\frac{4(17in^{2}) }{2}$

Area of trapezoid= $\frac{68in^{2} }{2}$

Area of trapezoid= $34in^{2}$

Add the area of the trapezoid to the area of the rectangle to find the total area: 50 in²+34 in²=84 in²

3 0

2 years ago