See the attached picture to better understand the problem

we know that
in the right triangle ABC
tan 68°=opposite side angle 68/adjacent side angle 68
opposite side angle 68=AB----- height of the tree
adjacent side angle 68=BC-----> 14.3 m
so
tan 68=AB/BC-----> solve for AB
AB=BC*tan 68-----> AB=14.3*tan 68------> AB=35.39 m------> AB=35.4 m

the answer is
the height of the tree is 35.4 m

7 0

3 years ago

1/2a - 4 = 6 try and answer this question

patriot [66]

Answer:

a = 20

Step-by-step explanation:

1/2a - 4 = 6

+4 +4

--------------------

1/2a = 10

*2 *2

---------------------

1a = 20

/1 /1

----------------------

a = 20<em> -------------------> answer</em>

5 0

2 years ago

Read 2 more answers

Find the equation of the line.<br> Use exact numbers.

likoan [24]

Answer:

y=3/4x-2

Step-by-step explanation:

y=mx+b

the b is the y-intercept so find the y-intercept of the line:

which is -2

the slope you need to find two points and look how many times do you need to rise or run to get the answer: 3/4

Hope this helps!

6 0

3 years ago

The height of an overhand volleyball serve can be modeled as h=-16t^2+20t+6. After how many seconds is the ball 11 feet.

Andrew [12]

Answer:

0.9043secs and 0.3456secs

Step-by-step explanation:

Given the height of an overhand volleyball modeled as h=-16t^2+20t+6.

If the height is 11feet, then;

11 = -16t^2+20t+6.

-16t^2+20t+6 - 11 = 0

-16t^2+20t-5 = 0

Multiply thriugh by -1

16t^2-20t+5 = 0

Factorize

t = 20±√20²-4(16)(5)/2(16)

t = 20 ±√400-320/32

t = 20 ±√80/32

t = 20 ±4√5/32

t = 20±8.94/32

t = 28.94/32 and 11.06/32

t = 0.9043 and 0.3456

Hence the required time are 0.9043secs and 0.3456secs

8 0

3 years ago