Question

P – 3 1/5 = 7 1/3 A. p = 107/15 B. p = 108/15 C. p = 118/15

Answer 1

$p-3\dfrac{1}{5}=7\dfrac{1}{3}\qquad\text{add}\ 3\dfrac{1}{5}\ \text{to both sides}\\\\p=7\dfrac{1}{3}+3\dfrac{1}{5}\qquad\text{find the common denominator}\to\ \text{it's 15}\\\\p=7\dfrac{1\cdot5}{3\cdot5}+3\dfrac{1\cdot3}{5\cdot3}\\\\p=7\dfrac{5}{15}+3\dfrac{3}{15}\\\\p=(7+3)+\left(\dfrac{5}{15}+\dfrac{3}{15}\right)\\\\p=10+\dfrac{5+3}{15}\\\\\boxed{p=10\dfrac{8}{15}}\to\boxed{B.}$

Answer 2

Answer:

B. p = 10  8/15

Step-by-step explanation:

p – 3 1/5 = 7 1/3

Add 3 1/5 to each side

p – 3 1/5 + 3 1/5 = 7 1/3 + 3 1/5

p = 7 1/3 + 3 1/5

Get a common denominator of 15

p = 10  + (1/3*5/5 + 1/5*3/3)

p = 10 + (5/15 + 3/15)

p = 10 + 8/15

p = 10 8/15