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Crank
3 years ago
9

Find the missing factor x^2-11x+18=(x-2)( )

Mathematics
1 answer:
tia_tia [17]3 years ago
4 0
I'd use synthetic div. here, with 2 as my divisor:

      ________________
2   /   1    -11    18
                  2   -18
     ----------------------------
         1     -9      0

Note that the coefficients of the missing factor are given here and are 1 and -9.  Thus, (x-9) is the missing factor.
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A and C I’m pretty sure D is also equivalent to 5.
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A pooled variance is an estimated weighted variance made up of several different populations when the mean of each population ma
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Answer:

True

Step-by-step explanation:

Considering the above definition of Pooled Variance, the correct answer is TRUE.

This is because Pooled variance is used to determine the reasonable estimates of variance, where several repeated tests are expected at each value.

This helps to provide greater precision estimates of variance.

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The jogging track at Francine’s school is 3/4 mile long. Yesterday Francine completed two laps on the track. If she ran 1/3 of t
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1/2 of a mile

Step-by-step explanation:

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7 0
3 years ago
Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of
Naddik [55]

Answer:

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

Step-by-step explanation:

For each U.S. resident, there are only two outcomes possible. Either they have blood type AB, or they do not. This means that we can solve this problem using binomial probability distribution concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem, we have that:

50 U.S residents are sampled, so n = 50

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What is the probability that exactly 2 of the U.S. residents have blood type AB?

This is P(X = 2). So:

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 2) = C_{50,2}.(0.04)^{2}.(0.96)^{48} = 0.2762

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

5 0
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