X and y are proportional hence when y is multiplied by a number, x is multiplied by the same number.
18=6*3 hence when y=18,x=9*3=27
x=27
1/7+2x/3=(15x-3)/21 make all terms have a common denominator of 21
3+14x=15x-3 subtract 3 from both sides
14x=15x-6 subtract 15x from both sides
-x=-6 divide both sides by -1
x=6
*Notice the use of parentheses in this format to make it clear what the numerators and denominators are...
Answer:b
Step-by-step explanation: $0.50 a year
Answer:

Step-by-step explanation:
As 2 and 7 are the only prime divisors of both
and
we know that both can be written as:

Where
is the set of all natural numbers adding the zero (careful because this part is important as I'll explain next).
We also know that 14 divides both numbers and that is actually the greatest common divisor between them. So we can rewrite a and b as follows:

Why do I write them like this? Because this way is easier to observe that if
and
were both greater than zero, then 28 would divide both hence 14 wouldn't be their g.c.d.. Likewise, if
and
were both greater than zero, then 98 would divide both and once again, 14 wouldn't be their g.c.d.
So either of them has to be equal to zero. And then we have that

All we have left to do is find the possible values for
and
so that
and that only happens if
and 
Answer:
20/7
Step-by-step explanation:
Check the picture