Question

X = -8 ± √(8)^2 - 4(1)(12) ---------- 2(1)

Answer 1

$x=\frac{-8\pm\sqrt{8^2-4(1)(12)}}{2(1)}\\x=\frac{-8\pm\sqrt{64-48}}{2}\\x=\frac{-8\pm\sqrt{16}}{2}\\x=\frac{-8\pm\sqrt{16}}{2}\\x =\frac{-8\pm4}{2}\\x=\frac{-8+4}{2} \ or \ \frac{-8-4}{2}\\x=\frac{-4}{2} \ or \ \frac{-12}{2}\\x=-2 \ or \ x=-6$